问题描述
我的Firestore文档中有一个投票"字段，其中存储了对该文档进行投票的人员的uid.
I have a votes field in my firestore documents, in which I store the uids of the people that have voted on that document.
我想调用所有文档，并按投票对象中的投票数对其进行排序.
I would like to call all the documents and order them by the number of votes in the votes object.
我尝试了db.collection('myCollection').orderBy(Object.keys('votes').length)...，但是作为orderBy参数无效.
I tried db.collection('myCollection').orderBy(Object.keys('votes').length)... but that is not valid as an orderBy parameter.
我也尝试过'votes.size'，但是没有运气.
I also tried 'votes.size' but no luck.
有什么方法可以按照Firebase Firestore中对象的长度来排序查询结果?
Is there any way to order results of a query by the length of an object in the firebase firestore?
推荐答案
在文档中添加votesCount键，并使用firebase函数在每次投票时重新计算计数.然后订购.
Add a votesCount key to the documents and a firebase function that recalculates the count every time there is a vote. Then order on that.
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