问题描述
我对以下内容感兴趣:
是否有一个字符列表永远不会作为 base 64 编码字符串的一部分出现?
例如 *
.我不确定这是否会发生.如果原始输入实际上有 *
作为它的一部分,那么它的编码方式会不同吗?
I am interested in the following:
Is there a list of characters that would never occur as part of a base 64 encoded string?
For example *
. I am not sure if this would occur or not. If the original input actually had *
as part of it would that be encoded differently?
推荐答案
这里是我可以找到的:RFC 4648
它包括这个方便的表格:
It includes this convenient table:
Table 1: The Base 64 Alphabet
Value Encoding Value Encoding Value Encoding Value Encoding
0 A 17 R 34 i 51 z
1 B 18 S 35 j 52 0
2 C 19 T 36 k 53 1
3 D 20 U 37 l 54 2
4 E 21 V 38 m 55 3
5 F 22 W 39 n 56 4
6 G 23 X 40 o 57 5
7 H 24 Y 41 p 58 6
8 I 25 Z 42 q 59 7
9 J 26 a 43 r 60 8
10 K 27 b 44 s 61 9
11 L 28 c 45 t 62 +
12 M 29 d 46 u 63 /
13 N 30 e 47 v
14 O 31 f 48 w (pad) =
15 P 32 g 49 x
16 Q 33 h 50 y
因此,匹配任何应该从不出现在 Base 64 编码中的字符的正则表达式将是:
So a regular expression that matches any character that should never appear in Base 64 encodings would be:
[^A-Za-z0-9+/=]
然而,正如 kapeps 的回答所指出的,这只是建议.特定的实现可能会选择一组不同的 64 个字符.(事实上,即使链接的 RFC 也包含一个用于 URL 和文件名安全编码的替代表,它分别用 -
和 _
替换了字符 62 和 63).所以我想这真的取决于创建编码的实现.
However, as kapeps answer points out, this is only the recommendation. Specific implementations might choose a different set of 64 characters. (In fact, even the linked RFC contains an alternative table for URL and filename safe encoding, which replaces character 62 and 63 with -
and _
respectively). So I guess it really depends on the implementation that created the encoding.
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