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问题描述

我想打印路由器配置和排序只是开始模式加密ISAKMP密钥6行。重要的是，我要离开了，在同一个地方行，因此所有之前这行后，应该留在同一个地方（不排序）。

I'd like to print router configuration and sort only lines starting with pattern "crypto isakmp key 6". Important thing is that I want to leave that lines in same place so all before and after this lines should stay in same place ( not sorted ).

例CFG文件：

123 345
678 901
bla bla bla
ble ble ble
crypto isakmp key 6 kokofeofepokpfowkfpwjeiofjwiojefiow address 123.456.789.012
crypto isakmp key 6 ofjwiojefiow352okdwofkwkfi9i42kpfsej09f09j4 address 123.456.789.012
crypto isakmp key 6 9i42kpfsej09f09j4ofjwiojefiow352okdwofkwkfi address 123.456.789.012
crypto isakmp key 6 9j4ofjwiojefiow352okdwofkwkfi9i42kpfsej09f0 address 123.456.789.012
ccc ddd eee
fff ggg hhh iii
123 456

所以，首先我想打印不变（行随机数）：

So first I'd like to print unchanged ( random count of rows ):

123 345
678 901
bla bla bla
ble ble ble

然后我想打印SORTED线开始加密ISAKMP密钥6。

Then i want to print SORTED lines starting with crypto isakmp key 6.

最后我想打印文件不变的其余部分（行也随机数）：

At the end i'd like to print rest of file unchanged ( also random count of rows ):

ccc ddd eee
fff ggg hhh iii
123 456

我已经被很多操作，包括获取第一个和最后一个位置加密ISAKMP密钥6，用的尾 / 头的命令，管理这一点，但它是相当复杂的，我不知道是否有在AWK / SED选项也许其它的Linux工具来管理它指定行。请解释一下你的命令的步骤一样。

I've managed this by many operations including getting 1st and last position of "crypto isakmp key 6" and using tail / head commands but it's quite complicated and I wonder if there is option in AWK/SED maybe other linux tool to manage it for specified lines. Please explain what Your command does in steps.

预计输出（加密排列完好休息）：

Expected output ( crypto sorted rest intact ):

123 345
678 901
bla bla bla
ble ble ble
crypto isakmp key 6 9i42kpfsej09f09j4ofjwiojefiow352okdwofkwkfi address 123.456.789.012
crypto isakmp key 6 9j4ofjwiojefiow352okdwofkwkfi9i42kpfsej09f0 address 123.456.789.012
crypto isakmp key 6 kokofeofepokpfowkfpwjeiofjwiojefiow address 123.456.789.012
crypto isakmp key 6 ofjwiojefiow352okdwofkwkfi9i42kpfsej09f09j4 address 123.456.789.012
ccc ddd eee
fff ggg hhh iii
123 456

问候，
迈克

Greetings,Mike

说明

y=/crypto isakmp key 6/
 #variable y is set to 1 if the line contains this regex, 0 if not
{
 #The following code block within the brackets is executed if y is non zero
x=1
 #Set x to 1(i.e true),done every match because it is less hassle and has no negative
 #side effects
a[NR]=$0
 #Create array element in array a with a key of NR(line number,doesn't actually matter what
 #it is though just has to be unique each line) and a value of $0(the line)
}
 #End that block
x&&!y
 #If x(set in the previous block to 1) is set and y isn't (meaning we have encountered a
 #crypto line but the one we are currently on isn't a crypto line) then
{
 #Open block like before
x=asort(a)
 #Sort the array a, and set x to the number of elements
for(i=1;i<=x;i++)
 #for each element
print a[i]
 #Print the element , note the loop ends here as we have not enclosed in brackets
x=0
 #Set x to 0(false)
}
 #End block
!x
 #Default action for awk is to print the line if an command returns true, so will print any
 #line where x is not set or is 0 i.e not crypto lines. We could have also used y'

使用有意义的名称

awk 'InBlock=/crypto isakmp key 6/{Stored=1;Lines[NR]=$0}
     Stored&&!InBlock{
         Count=asort(Lines)
         for(i=1;i<=Count;i++)print Lines[i]
         Stored=0
     }
     !InBlock' file

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首先是模式BASH排序行

首先是模式BASH排序行

问题描述

推荐答案

说明

使用有意义的名称