如何检查字符串是否在Bash中包含子字符串

问题描述

我在Bash中有一个字符串:

I have a string in Bash:

string="My string"

如何测试它是否包含另一个字符串?

How can I test if it contains another string?

if [ $string ?? 'foo' ]; then
  echo "It's there!"
fi

??是我的未知运算符.我是否使用echo和grep?

Where ?? is my unknown operator. Do I use echo and grep?

if echo "$string" | grep 'foo'; then
  echo "It's there!"
fi

看起来有点笨拙.

推荐答案

您可以使用 Marcus的答案(*通配符)如果您使用双括号，也可以在case语句之外:

You can use Marcus's answer (* wildcards) outside a case statement, too, if you use double brackets:

string='My long string'
if [[ $string == *"My long"* ]]; then
  echo "It's there!"
fi

请注意，针串中的空格必须放在双引号之间，并且*通配符应位于外部.另外请注意，使用的是简单的比较运算符(即==)，而不是正则表达式运算符=~.

Note that spaces in the needle string need to be placed between double quotes, and the * wildcards should be outside. Also note that a simple comparison operator is used (i.e. ==), not the regex operator =~.

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