问题描述
我有两个顶点类：位置和用户和我有两个边缘：Friend和GoingTo。用户可以是与另一个用户的朋友，并且用户也可以去到一个位置。边缘GoingTo有一个datetime属性叫go_date，用户要去的位置的日期。
I have two vertex classes: Location and User and I have two edges also: Friend and GoingTo. A User can be 'Friend' with another User and a User can also 'GoingTo' a Location. The edge GoingTo has a datetime property called going_date with the date the user is going to the Location.
我想返回每个位置 ）边缘从作为特定起始用户（作为示例＃12：11）的（朋友）的用户。
I want to return every ‘Location’ that has a in("GoingTo") edge from an ‘User’ that is a ("Friend") of a specific starting ‘User’ (#12:11 as example).
这里是所有的位置，但没有日期属性的goingTo ...
What I have here is all locations but without the date property of goingTo...
SELECT expand(both('Friend').out('goingTo')) FROM #12:11
如何通过边缘属性查询？ p>
How can I query by this edge property?
推荐答案
您可以过滤边缘的属性：
You can filter on edge's property:
SELECT expand（both（'Friend'）。outE（'goingTo'）[going_date ='2015-01-01']。inV（））FROM＃12：11
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