问题描述
可能重复:
为什么 XML-Serializable 类需要无参数构造函数
我正在尝试在我的代码中序列化一个元组:
I'm trying to serialize a tuple in my code:
List<List<Tuple<String, CodeExtractor.StatementNode>>> results = null;
results = extractor.ExtractSourceCode(sourceCode);
FileStream fs = new FileStream(@"C:ProjectsTestast.xml", FileMode.Create);
XmlSerializer formatter = new XmlSerializer(
typeof(List<List<Tuple<String, CodeExtractor.StatementNode>>>));
formatter.Serialize(fs, results);
fs.Close();
但它失败了并像这样捕获异常:
but it was failed and catch the exception like this:
System.Tuple`2[System.String,CodeExtractor.StatementNode] 无法序列化,因为它没有无参数构造函数.
我确信 CodeExtractor.StatementNode
可以被序列化.
and I'm do sure the CodeExtractor.StatementNode
could be serialized.
推荐答案
为了 XmlSerializer
能够完成它的工作,它需要一个默认的构造函数.那是一个不带参数的构造函数.所有 Tuple<...>
类都有一个构造函数,并且该构造函数接受多个参数.元组中的每个值一个.所以在你的情况下,唯一的构造函数是
For XmlSerializer
to be able to do its job it needs a default contructor. That is a constructor that takes no arguments. All the Tuple<...>
classes have a single constructor and that constructor takes a number of arguments. One for each value in the tuple. So in your case the sole constructor is
Tuple(T1 value1, T2 value2)
序列化程序正在寻找一个不带参数的构造函数,但因为找不到它,所以你得到了异常.
The serializer is looking for a constructor with no arguments and because it can't find it, you get the exception.
你可以创建一个可变类,它可以代替元组来进行序列化
you could create a mutable class, that could be substituted for tuples for the purpose of serialization
class MyTuple<T1, T2>
{
MyTuple() { }
public T1 Item1 { get; set; }
public T2 Item2 { get; set; }
public static implicit operator MyTuple<T1, T2>(Tuple<T1, T2> t)
{
return new MyTuple<T1, T2>(){
Item1 = t.Item1,
Item2 = t.Item2
};
}
public static implicit operator Tuple<T1, T2>(MyTuple<T1, T2> t)
{
return Tuple.Create(t.Item1, t.Item2);
}
}
你可以通过以下方式使用它
You could then use it the following way
XmlSerializer formatter = new XmlSerializer(
typeof(List<List<MyTuple<String, CodeExtractor.StatementNode>>>));
formatter.Serialize(fs, results.SelectMany(
lst => lst.Select(
t => (MyTuple)t
).ToList()
).ToList());
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