如何在内存中创建文件对象

问题描述

我想制作一个内存文件以在pygame混合器中使用.我的意思是这样的( http://www.pygame .org/docs/ref/music.html#pygame.mixer.music.load 它表示load()方法支持文件对象)

I want to make a in-memory file to use in pygame mixer. I mean something like that (http://www.pygame.org/docs/ref/music.html#pygame.mixer.music.load it says load() method supports file object)

import requests
from pygame import mixer

r = requests.get("http://example.com/some_small_file.mp3")
in_memory_file = file(r.content) #something like that
mixer.music.init()
mixer.music.load(in_memory_file)
mixer.music.play()

推荐答案

您可能正在从Python io包中寻找BytesIO或StringIO类，这两个类均在 Python 2 和 Python 3 .它们提供了类似于文件的界面，您可以在代码中使用与真实文件进行交互的方式完全相同.

You are probably looking for BytesIO or StringIO classes from Python io package, both available in python 2 and python 3. They provide a file-like interface you can use in your code the exact same way you interact with a real file.

StringIO用于存储文本数据:

import io

f = io.StringIO("some initial text data")

BytesIO必须用于二进制数据:

BytesIO must be used for binary data:

import io

f = io.BytesIO(b"\x00\x00\x00\x00\x00\x00\x00\x00\x01\x01\x01\x01\x01\x01")

要存储MP3文件数据，您可能需要BytesIO类.要将其从GET请求初始化到服务器，请按以下步骤操作:

To store MP3 file data, you will probably need the BytesIO class. To initialize it from a GET request to a server, proceed like this:

import requests
from pygame import mixer
import io

r = requests.get("http://example.com/somesmallmp3file.mp3")
inmemoryfile = io.BytesIO(r.content)

mixer.music.init()
mixer.music.load(inmemoryfile)
mixer.music.play()

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