python:更改符号变量并分配数值

问题描述

为了计算导数和其他表达式，我使用了 sympy 包并说 T = sy.Symbol('T') 现在我已经计算了正确的表达式:

E= -T**2*F_deriv_T(T,rho)

哪里

def F_deriv_rho(T,rho):ret = 0对于范围内的 n(5):对于范围内的 m(4):内部= c[n,m]*g_rho_deriv_rho_np*g_T_npret += 内部返回 ret

看起来像这样:

F_deriv_rho: [0.0 7.76971e-5*T 0.0001553942*T**2*rhoT*(-5.14488e-5*log(rho) - 5.14488e-5)*log(T) + T*(1.22574e-5*log(rho)+1.22574e-5)*log(T) + T*(1.89488e-5*log(rho) + 1.89488e-5)*log(T) + T(2.29441e-5*log(rho) + 2.29441e-5)*log(T) + T*(7.49956)e-5*log(rho) + 7.49956e-5)*log(T)T**2*(-0.0001028976*rho*log(rho) - 5.14488e-5*rho)*log(T) + T**2*(2.45148e-5*rho*log(rho) + 1.22574e-5*rho)*log(T) + T**2*(3.78976e-5*rho*log(rho) + 1.89488e-5*rho)*log(T) + T**2*(4.58882e-5*rho*log(rho) + 2.29441e-5*rho)*log(T) + T**2*(0.0001499912*rho*log(rho) + 7.49956e 5*rho)*log(T)]

使用 python 我想将 T(和 rho)作为一个符号更改为一个值.我怎么能这样做?

所以，我想创建 10 个数字，例如 T_def = np.arange(2000, 10000, 800) 并交换我所有的 sy.symbol(T) 通过迭代我在数组中创建的 10 个值.

感谢您的帮助

解决方案

我根据这篇文章找到了解决方案:

如何替换表达式中的多个符号同情?

通过使用subs":

>>>从 sympy 导入符号>>>x, y = Symbol('x y')>>>f = x + y>>>f.subs({x:10, y: 20})>>>F30

这里有更多关于这种事情的内容:http://docs.sympy.org/最新/教程/basic_operations.html

更快的方法是使用@Bjoern Dahlgren 建议的lamdify"

In order to calculate derivatives and other expressions I used the sympy package and said that T = sy.Symbol('T') now that I have calculated the right expression:

E= -T**2*F_deriv_T(T,rho)

where

def F_deriv_rho(T,rho):
    ret = 0
    for n in range(5):
        for m in range(4):
            inner= c[n,m]*g_rho_deriv_rho_np*g_T_np
        ret += inner
    return ret

that looks like this:

F_deriv_rho: [0.0 7.76971e-5*T 0.0001553942*T**2*rhoT*(-5.14488e-5*log(rho) - 5.14488e-5)*log(T) + T*(1.22574e-5*log(rho)+1.22574e-5)*log(T) + T*(1.89488e-5*log(rho) + 1.89488e-5)*log(T) + T(2.29441e-5*log(rho) + 2.29441e-5)*log(T) + T*(7.49956e-5*log(rho) + 7.49956e-5)*log(T) T**2*(-0.0001028976*rho*log(rho) - 5.14488e-5*rho)*log(T) + T**2*(2.45148e-5*rho*log(rho) + 1.22574e-5*rho)*log(T) + T**2*(3.78976e-5*rho*log(rho) + 1.89488e-5*rho)*log(T) + T**2*(4.58882e-5*rho*log(rho) + 2.29441e-5*rho)*log(T) + T**2*(0.0001499912*rho*log(rho) + 7.49956e 5*rho)*log(T)]

with python I would like to change T (and rho) as a symbol to a value. How could I do that?

So, I would like to create 10 numbers like T_def = np.arange(2000, 10000, 800)and exchange all my sy.symbol(T) by iterating through the 10 values I created in the array.

Thanks for your help

解决方案

I have found the solution according to this post:

How to substitute multiple symbols in an expression in sympy?

by usings "subs":

>>> from sympy import Symbol
>>> x, y = Symbol('x y')
>>> f = x + y
>>> f.subs({x:10, y: 20})
>>> f
    30

There's more for this kinda thing here: http://docs.sympy.org/latest/tutorial/basic_operations.html

EDIT: A faster way would be by using "lamdify" as suggested by @Bjoern Dahlgren

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