Matlab 中的行程编码

问题描述

我对 MatLab 很陌生，我有运行长度编码代码，但似乎不起作用，你能帮我吗?

I'm very new with MatLab, I have Run Length Encoding code but it seems to not work, can you help me?

我有这个输入:

ChainCode  = 11012321170701000700000700766666666666665555555544443344444333221322222322

我想把它变成 RLE 输出:

and I want make it into RLE output :

(1,2), (0,1), (1,1), (2,1), (3,1), (2,1), (1,2), (7,1), (0,1), (7,1), (0,1),
(1,1), (0,3), (7,1), (0,5), (7,1), (0,2), (7,1), (6,13), (5,8), (4,4), (3,2),
(4,5), (3,3), (2,2), (1,1), (3,1), (2,5), (3,1), (2,2)

这是我的代码:

lengthcode = 1;
N = 1;

for i = 2:length(ChainCode)

    if x(i)==x(i-1)
        N = N + 1;
        valuecode(N)  = x(i);
        lengthcode(N) = lengthcode(N) + 1;
    else
        N = 1;
        lengthcode = 1;
    end

    i = i + 1;

end

但这不起作用，我仍然对如何打印这样的输出感到困惑.

But this is not working, and I am still confused about how can I print the output like that.

我希望你能帮助我.谢谢你.

I hope you can help me. Thank you.

推荐答案

这是一个没有循环、cellfun 或 arrayfun 的紧凑解决方案:

Here is a compact solution without loop, cellfun or arrayfun:

chainCode = '11012321170701000700000700766666666666665555555544443344444333221322222322';
numCode = chainCode - '0'; % turn to numerical array

J=find(diff([numCode(1)-1, numCode]));
relMat=[numCode(J); diff([J, numel(numCode)+1])];

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