R:计算单列和组中连续出现的值

问题描述

我正在尝试创建一系列相等的值，即出现次数.但是，即使行保持顺序，我也希望在引入新 ID 后重置计数.

I am trying to create a sequential number of equal values, a count of occurrences. However, I want the count to reset once a new ID is introduced even if the the row remains sequential.

我的数据示例:

dataset <- data.frame(ID =
c("a","a","a","a","a","a","a","b","b","b","b","b","b","b")
dataset$YesNO <- c(1,1,0,0,0,1,1,1,1,1,0,0,0,0)

所以我想创建一个新列，结果如下:

So I want to create a new column with the results in:

c(1,2,1,2,3,1,2,1,2,3,1,2,3,4)

我使用了在此论坛上找到的代码:

I've used this code that I've found on this forum:

dataset$Counter <- sequence(rle(as.character(dataset$YesNo))$lengths)

但是，这不会重置新 ID 号的计数.相反，顺序计数继续，结果输出为:

However, this doesn't reset the count for the new ID number. Instead the sequential count continues and the resulting output is:

c(1,2,1,2,3,1,2,3,4,5,1,2,3,4)

我错过了根据 ID 重置它的步骤.

What step am I missing to have it reset based on the ID.

谢谢！

推荐答案

使用rleid(来自data.table包)得到一个分组变量，然后使用ave在该分组的通用值中应用 seq_along:

Use rleid (from the data.table package) to get a grouping variable and then use ave to apply seq_along within common values of that grouping:

library(data.table)
transform(dataset, Counter = ave(YesNO, rleid(ID, YesNO), FUN = seq_along))

给予:

   ID YesNO Counter
1   a     1       1
2   a     1       2
3   a     0       1
4   a     0       2
5   a     0       3
6   a     1       1
7   a     1       2
8   b     1       1
9   b     1       2
10  b     1       3
11  b     0       1
12  b     0       2
13  b     0       3
14  b     0       4

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