问题描述
VB6似乎不容易将+ infinity,-infinity和NaN存储到双变量中.如果可以的话,这将有所帮助,以便我可以在复数的情况下与这些值进行比较.怎么样?
VB6 doesn't appear to make it that easy to store +infinity, -infinity and NaN into double vars. It would help if it could so that I could do comparisons with those values in the context of complex numbers. How?
推荐答案
一些不同的东西.从Pax的示例中可以看到,您确实只需要查找IEEE 754标准,然后将字节插入正确的位置.我唯一要注意的是, MicroSoft已弃用RtlMoveMemory ,因为它有可能造成溢出类型的安全性问题.作为替代方案,您可以使用用户定义的类型和LSet在纯" VB中稍加强制地完成此操作. (还要注意,NaN有两种类型.)
A few different things. As you can see from Pax's example, you really just need to look up the IEEE 754 standard and then plug your bytes into the right places. The only caution I would give you is that MicroSoft has deprecated RtlMoveMemory due to it's potential for creating security issues of the overflow type. As an alternative you can accomplish this in "pure" VB with a little careful coercion using User Defined Types and LSet. (Also note that there are two types of NaN.)
Option Explicit
Public Enum abIEEE754SpecialValues
abInfinityPos
abInfinityNeg
abNaNQuiet
abNaNSignalling
abDoubleMax
abDoubleMin
End Enum
Private Type TypedDouble
value As Double
End Type
Private Type ByteDouble
value(7) As Byte
End Type
Public Sub Example()
MsgBox GetIEEE754SpecialValue(abDoubleMax)
End Sub
Public Function GetIEEE754SpecialValue(ByVal value As abIEEE754SpecialValues) As Double
Dim dblRtnVal As Double
Select Case value
Case abIEEE754SpecialValues.abInfinityPos
dblRtnVal = BuildDouble(byt6:=240, byt7:=127)
Case abIEEE754SpecialValues.abInfinityNeg
dblRtnVal = BuildDouble(byt6:=240, byt7:=255)
Case abIEEE754SpecialValues.abNaNQuiet
dblRtnVal = BuildDouble(byt6:=255, byt7:=255)
Case abIEEE754SpecialValues.abNaNSignalling
dblRtnVal = BuildDouble(byt6:=248, byt7:=255)
Case abIEEE754SpecialValues.abDoubleMax
dblRtnVal = BuildDouble(255, 255, 255, 255, 255, 255, 239, 127)
Case abIEEE754SpecialValues.abDoubleMin
dblRtnVal = BuildDouble(255, 255, 255, 255, 255, 255, 239, 255)
End Select
GetIEEE754SpecialValue = dblRtnVal
End Function
Public Function BuildDouble( _
Optional byt0 As Byte = 0, _
Optional byt1 As Byte = 0, _
Optional byt2 As Byte = 0, _
Optional byt3 As Byte = 0, _
Optional byt4 As Byte = 0, _
Optional byt5 As Byte = 0, _
Optional byt6 As Byte = 0, _
Optional byt7 As Byte = 0 _
) As Double
Dim bdTmp As ByteDouble, tdRtnVal As TypedDouble
bdTmp.value(0) = byt0
bdTmp.value(1) = byt1
bdTmp.value(2) = byt2
bdTmp.value(3) = byt3
bdTmp.value(4) = byt4
bdTmp.value(5) = byt5
bdTmp.value(6) = byt6
bdTmp.value(7) = byt7
LSet tdRtnVal = bdTmp
BuildDouble = tdRtnVal.value
End Function
最后一点说明,您也可以通过以下方式获得NaN:
One last side note, you can also get NaN this way:
Public Function GetNaN() As Double
On Error Resume Next
GetNaN = 0 / 0
End Function
这篇关于如何使VB6用+ infinity,-infinity和NaN初始化双精度型?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!