pandas 不会到位fillna()

本文介绍了 pandas 不会到位fillna()的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我正在尝试在数据帧的4个特定列(即字符串/对象类型)中用"填充NA.我可以在fillna()时将这些列分配给新变量，但是当我填充fillna()时，基础数据不会更改.

I'm trying to fill NAs with "" on 4 specific columns in a data frame that are string/object types. I can assign these columns to a new variable as I fillna(), but when I fillna() inplace the underlying data doesn't change.

a_n6 = a_n6[["PROV LAST", "PROV FIRST", "PROV MID", "SPEC NM"]].fillna("")
a_n6

给我:

<class 'pandas.core.frame.DataFrame'>
Int64Index: 1542 entries, 0 to 3611
Data columns (total 4 columns):
PROV LAST     1542  non-null values
PROV FIRST    1542  non-null values
PROV MID      1542  non-null values
SPEC NM       1542  non-null values
dtypes: object(4)

但是

a_n6[["PROV LAST", "PROV FIRST", "PROV MID", "SPEC NM"]].fillna("", inplace=True)
a_n6

给我:

<class 'pandas.core.frame.DataFrame'>
Int64Index: 1542 entries, 0 to 3611
Data columns (total 7 columns):
NPI           1103  non-null values
PIN           1542  non-null values
PROV FIRST    1541  non-null values
PROV LAST     1542  non-null values
PROV MID      1316  non-null values
SPEC NM       1541  non-null values
flag          439  non-null values
dtypes: float64(2), int64(1), object(4)

只有一排，但仍然令人沮丧.我在做什么错了?

It's just one row, but still frustrating. What am I doing wrong?

使用`dict`作为`fillna()`

的value自变量

正如@rhkarls在@Jeff的答案中的评论中所述，使用索引到列列表的.loc将不支持inplace操作，这也让我感到沮丧.这是一种解决方法.

Use a `dict` as the `value` argument to `fillna()`

As mentioned in the comment by @rhkarls on @Jeff's answer, using .loc indexed to a list of columns won't support inplace operations, which I too find frustrating. Here's a workaround.

示例:

import pandas as pd
import numpy as np

df = pd.DataFrame({'a':[1,2,3,4,np.nan],
                   'b':[6,7,8,np.nan,np.nan],
                   'x':[11,12,13,np.nan,np.nan],
                   'y':[16,np.nan,np.nan,19,np.nan]})
print(df)
#     a    b     x     y
#0  1.0  6.0  11.0  16.0
#1  2.0  7.0  12.0   NaN
#2  3.0  8.0  13.0   NaN
#3  4.0  NaN   NaN  19.0
#4  NaN  NaN   NaN   NaN

假设我们只想fillna仅用于x和y，不 a和b.

Let's say we want to fillna for x and y only, not a and b.

我希望使用.loc可以正常工作(就像在作业中一样)，但是不能使用，如前所述:

I would expect using .loc to work (as in an assignment), but it doesn't, as mentioned earlier:

# doesn't work
df.loc[:,['x','y']].fillna(0, inplace=True)
print(df) # nothing changed

但是，文档表示， fillna()的value参数可以是:

However, the documentation says that the value argument to fillna() can be:

事实证明，使用值的字典将起作用:

It turns out that using a dict of values will work:

# works
df.fillna({'x':0, 'y':0}, inplace=True)
print(df)
#     a    b     x     y
#0  1.0  6.0  11.0  16.0
#1  2.0  7.0  12.0   0.0
#2  3.0  8.0  13.0   0.0
#3  4.0  NaN   0.0  19.0
#4  NaN  NaN   0.0   0.0

此外，如果子集中有很多列，则可以使用dict理解，如:

Also, if you have a lot of columns in your subset, you could use a dict comprehension, as in:

df.fillna({x:0 for x in ['x','y']}, inplace=True) # also works

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fillna