在CUDA多precision乘法

问题描述

我想实现在CUDA多precision倍增。对于这样做，我已经实现，应计算 uint32_t的的乘法256位操作数类型，并把结果在288位阵列的内核。到目前为止，我已经想出了这个code：

I am trying to implement multi-precision multiplication in CUDA. For doing that, I have implemented a kernel which should compute multiplication of uint32_t type operand with 256-bit operand and put the result in 288-bit array. So far, I have came up with this code:

__device__ __constant__ UN_256fe B_const;

 __global__ void multiply32x256Kernel(uint32_t A, UN_288bite* result){

uint8_t tid = blockIdx.x * blockDim.x + threadIdx.x;
//for managing warps
//uint8_t laineid = tid % 32;
//allocate partial products into array of uint64_t
__shared__ uint64_t partialMuls[8];
uint32_t carry, r;
if((tid < 8) && (tid != 0)){
    //compute partial products
    partialMuls[tid] = A * B_const.uint32[tid];

    //add partial products and propagate carry
    result->uint32[8] = (uint32_t)partialMuls[7];
    r = (partialMuls[tid] >> 32) + ((uint32_t)partialMuls[tid - 1]);
    carry = r < (partialMuls[tid] >> 32);
    result->uint32[0] = (partialMuls[0] >> 32);
    while(__any(carry)){

        r = r + carry;
        //new carry?
        carry = r < carry;
    }
result->uint32[tid] = r;

}

和我的数据类型是：

typedef struct UN_256fe{

uint32_t uint32[8];

}UN_256fe;

typedef struct UN_288bite{

uint32_t uint32[9];

}UN_288bite;

我的内核工作，但它给了我错误的结果。我不能在内核中进行调试，所以我会AP preciate如果有人让我知道问题出在哪里或如何调试我的code中的内核中的的Tegra-的Ubuntu 与 CUDA-6.0 。
谢谢

推荐答案

这答案有没有关系CUDA本身，而是一般的C实现。

This answer has nothing to do with CUDA itself, but is a general C implementation.

我不能完全跟着你在做什么（尤其是执行），但你可以根据自己的大NUM功能试试这个片段。我定义的 DTYPE ，使其更容易与较小的领域进行测试。请注意，我没有具体使用执行，但发扬部分产品。

I can't quite follow what you are doing (especially with carry) but you could try this snippet based on my own big num functions. I defined dtype to make it easier to test with smaller fields. Note that I don't specifically use a carry, but carry forward the partial product.

// little-endian
#include <stdio.h>
#include <stdint.h>
#include <limits.h>

#define dtype uint8_t           // for testing
//#define dtype uint32_t        // for proper ver

#define SHIFTS (sizeof(dtype)*CHAR_BIT)
#define NIBBLES (SHIFTS/4)
#define ARRLEN 8

typedef struct UN_256fe {
    dtype uint[ARRLEN];
} UN_256fe;

typedef struct UN_288bite {
    dtype uint[ARRLEN+1];
} UN_288bite;

void multiply(UN_288bite *product, UN_256fe *operand, dtype multiplier)
{
    int i;
    uint64_t partial = 0;
    for (i=0; i<ARRLEN; i++) {
        partial = partial + (uint64_t)multiplier * operand->uint[i];
        product->uint[i] = (dtype)partial;
        partial >>= SHIFTS;                     // carry
    }
    product->uint[i] = (dtype)partial;
}

int main(void)
{
    int i;
    dtype multiplier = 0xAA;
    UN_256fe operand = { 1, 2, 3, 4, 5, 6, 7, 8};
    UN_288bite product;

    multiply(&product, &operand, multiplier);

    for(i=ARRLEN-1; i>=0; i--)
        printf("%0*X", NIBBLES, operand.uint[i]);
    printf("\n * %0*X = \n", NIBBLES, multiplier);
    for(i=ARRLEN; i>=0; i--)
        printf("%0*X", NIBBLES, product.uint[i]);
    printf("\n");

    return 0;
}

节目输出为 uint8_t有

0807060504030201
 * AA =
0554A9FF54A9FF54AA

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