layer为ggmap不承认data

layer为ggmap不承认data

本文介绍了创建base_layer为ggmap不承认data.frame的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想使用ggmap绘制在地图上的位置。因为我想用小面,我必须提供 base_layer 参数 ggmap 。我也试图在一个函数来包装这个。

我有定义我的地图边框变量:

  long.range<  -  C(-71.5,-67.5)
lat.range< - C(42.5,44.5)

和定义数据的data.frame我想绘制:

  test.data<  -  data.frame(名= C(站点1,站点2,site3),
                        LAT= C(43.25,43.4,44)
                        LONG= C(-71.25,-69.5,-68.5))

我有出去和抓住地图并应用data.frame作为base_layer功能:

  CreateBaseMap<  - 功能(lat.range = C(NA,NA)
                          long.range = C(NA,NA)
                          data.in = NULL){
  #下载地图图块
  base.map.in< - get_map(位置= C(分(long.range)
                                      分钟(lat.range)
                                      MAX(long.range)
                                      MAX(lat.range))
                         来源=OSM)
  #创建地图对象
  如果(is.null(data.in)){
    base.map< - ggmap(base.map.in)
  }其他{
    base.map< - ggmap(base.map.in,
                      base_layer = ggplot(aes_string(X =LONG,
                                                     Y =LAT),
                                          数据= data.in))
  }
  base.map< - base.map +
    实验室(X =经度,
         Y =纵横)+
    coord_map()
  打印(base.map)
  回报(base.map)
}

然后我用我的调用函数

  base.map<  -  CreateBaseMap(lat.range = lat.range,long.range = long.range,data.in = test.data)

和我得到这个错误。

 错误ggplot(aes_string(X =LONG,Y =LAT),数据= data.in):
  对象data.in'未找到

疑难解答至今

我知道,如果我直接调用该函数的胆量,像这样的:

  base.map<  -  ggmap(get_map(位置= C(分(long.range)
                                       分钟(lat.range)
                                       MAX(long.range)
                                       MAX(lat.range))
                          来源=OSM),
                  base_layer = ggplot(aes_string(X =LONG,
                                                 Y =LAT),
                                      数据= test.data))+
  geom_point()
打印(base.map)

然后正常工作。

我一直在使用打印(data.in)还检查的data.in存在,它获取到调用之前 base_layer ,我可以看到它的存在。

问题

看来,在调用 base_layer 不承认 data.in


  1. 如何说服 base_layer ,它真的要接受 data.in

  2. 这是 ggplot 有问题,还是我做错了什么?


解决方案

解决的办法似乎是使用%+% ggplot 即从 ggmap 调用创建的,而不是包括 base_layer 原调用项目 ggmap 。这绕过@baptiste确定的code问题。

要实现该方案,在以下code复制到位的#创建地图对象在我原来的问题:

 #创建地图对象
  如果(is.null(data.in)){
    base.map< - ggmap(base.map.in)
  }其他{
    base.map< - ggmap(base.map.in)%+%data.in + AES(X = LONG,
                                                      Y = LAT)
  }

I am trying to use ggmap to plot locations on a map. Because I want to use faceting, I have to supply the base_layer argument to ggmap. I am also trying to wrap this in a function.

I have variables that define the bounding box of my map:

long.range <- c(-71.5, -67.5)
lat.range <- c(42.5, 44.5)

And a data.frame that defines the data I want to plot:

test.data <- data.frame("Name" = c("site1","site2","site3"),
                        "LAT" = c(43.25,43.4,44),
                        "LONG" = c(-71.25,-69.5,-68.5))

I have a function that goes out and grabs the map and applies the data.frame as the base_layer:

CreateBaseMap <- function(lat.range = c(NA,NA),
                          long.range = c(NA,NA),
                          data.in = NULL){
  # download the map tile
  base.map.in <- get_map(location = c(min(long.range),
                                      min(lat.range),
                                      max(long.range),
                                      max(lat.range)),
                         source = "osm")
  # create the map object
  if (is.null(data.in)){
    base.map <- ggmap(base.map.in)
  } else {
    base.map <- ggmap(base.map.in,
                      base_layer = ggplot(aes_string(x = "LONG",
                                                     y = "LAT"),
                                          data = data.in))
  }
  base.map <- base.map +
    labs(x = "Longitude",
         y = "Latitude") +
    coord_map()
  print(base.map)
  return(base.map)
}

and then I call my function using

base.map <- CreateBaseMap(lat.range = lat.range, long.range = long.range, data.in = test.data)

and I get this error.

Error in ggplot(aes_string(x = "LONG", y = "LAT"), data = data.in) :
  object 'data.in' not found

Troubleshooting so far

I know if I call the guts of the function directly, like this:

base.map <- ggmap(get_map(location = c(min(long.range),
                                       min(lat.range),
                                       max(long.range),
                                       max(lat.range)),
                          source = "osm"),
                  base_layer = ggplot(aes_string(x = "LONG",
                                                 y = "LAT"),
                                      data = test.data)) +
  geom_point()
print(base.map)

then it works fine.

I have also checked using print(data.in) that the data.in exists before it gets to the call to base_layer, and I can see that it's there.

Question

It appears that the call to base_layer doesn't recognize data.in.

  1. How can I persuade base_layer that it really wants to accept data.in?
  2. Is this a problem with ggplot, or am I doing something wrong?
解决方案

The solution seems to be to use %+% on the ggplot item that is created from the ggmap call, rather than including base_layer in the original call to ggmap. This bypasses the code problem that @baptiste identified.

To implement this solution, copy in the following code in place of the #create the map object in my original question:

# create the map object
  if (is.null(data.in)){
    base.map <- ggmap(base.map.in)
  } else {
    base.map <- ggmap(base.map.in ) %+% data.in + aes(x = LONG,
                                                      y = LAT)
  }

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07-31 02:15