strstr()的参数计数错误

问题描述

我已经使用帖子GUID在wordpres中构建了一个导航菜单，并且发布了标题，我只使用了部分标题，为此，我将执行以下操作，

I have built a nav menu in wordpres using a posts GUID, and post title, I am taking only part of the title and to do this I am doing the following,

$casestudylist .= "<li class='subnav'><a href=".$v->guid.">". strstr($v->post_title, ":", true)."</a></li>";

但是我收到以下警告，但无法找出原因:

however I get the following warning and cannot work out why:

wrong parameter count for strstr()

基本上，我试图将所有字符从字符串中拉出，如果它们在:之前.

Basically I am trying to pull all the characters out of a string if they are before a :.

推荐答案

您使用的PHP版本不支持 strstr ，因此出现错误消息.您对该功能的使用要求PHP 5.3.0或更高版本.

The PHP version you're using does not support the third parameter of strstr, hence the error message. Your usage of the function requires PHP 5.3.0 or higher.

您可以在服务器上升级PHP版本，也可以将函数调用替换为类似的内容:

You can either upgrade the PHP version on your server or you replace the function call with something similar like:

substr($v->post_title, 0, strpos($v->post_title, ":"))

，或者如果您想使用易于阅读的帮助器功能(演示):

or if you want to use a helper function which is easier to read (Demo):

str_before($v->post_title, ":");

function str_before($subject, $needle)
{
    $p = strpos($subject, $needle);
    return substr($subject, 0, $p);
}

相关: strstr在出现之前显示字符串

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