问题描述
我需要基于参数检索或不从实体获得某些关联.在下面的示例中,仅当参数通过我的api传递时,我才需要获取记录列表.您能推荐一种使用休眠/弹簧数据实现此目的的方法吗?我正在寻找最干净,类似Spring数据的方法.
I need based on parameter retrieve or not some associations from an entity. In the bellow example I need to get the records list only if a parameter is passed through my api. Can you recommend a way of achieving this using hibernate/spring data? I'm looking for the most clean and spring data-like approach.
public class Customer {
private UUID id;
@OneToMany(mappedBy = "customer")
private List<Record> records = new ArrayList<>();
}
public class Record {
private UUID id;
@Column(name = "customer_id", length = 36, columnDefinition = "varchar(36)", nullable = false)
private UUID customerId;
@JoinColumn(name = "customer_id", insertable = false, updatable = false)
private Customer customer;
}
我的存储库为空:
public interface CustomerRepository extends JpaRepository<Customer, UUID> {
}
在我的服务中,我正在做类似的事情:
On my service I'm doing something like:
Customer customer = customerRepository.findById(customerId).orElseThrow(() -> new CustomerNotFoundException("customerId", customerId));
但是我想做的事情是这样的:
But what I would like to do is something like:
if (showRecords) {
Customer customer = customerRepository.findById(customerId).orElseThrow(() -> new CustomerNotFoundException("customerId", customerId));
} else {
Customer customer = customerRepository.findByIdWithoutAssociations(customerId).orElseThrow(() -> new CustomerNotFoundException("customerId", customerId));
}
推荐答案
如何使用基本的 findById
仅返回Customer对象,并使用另一种方法 findWithRecordsById
返回客户+使用 @EntityGraph
记录吗?
How about using the base findById
to return just the Customer object and have another method findWithRecordsById
to return customer+records using @EntityGraph
?
public interface CustomerRepository extends JpaRepository<Customer, UUID>{
@EntityGraph(attributePaths = {"records"})
Customer findWithRecordsById(UUID id);
...
}
这篇关于Spring Data JPA/休眠处理关联的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!