删除数组元素的JavaScript

问题描述

也许按标题似乎是一个简单的问题，但我didn't知道该怎么做最短的标题我的问题。结果
我想删除的JavaScript数组中的元素，是的，但我所寻找的究竟是来自于JavaScript与其他数组的数组元素不匹配（也许它可能是冠军，但过大）删除。结果
例如：

 阵列A =＆GT; [A B C D]
数组b =＆GT; [B，D]
阵C = deleteMismatchedElements（A，B）
阵C（功能之后） - ＆GT; [B，D]
 

我想，使用嵌套foreach循环也可能是可能的，但我不知道是否有更好的办法，一些作为原生实现的方法可以被称为或类似...

非常感谢你。

解决方案

 变种C = [];
对于（VAR I = 0; I＆LT; b.length个;我++）{
    如果（A.indexOf（B〔Ⅰ〕）-1个）{
        C.push（B [I]）;
    }
}
 

这样做是

1. 创建数组 C
2. 的每个项目，运行在 B
3. 如果 B [I] 是 A ，将其添加到 C

Maybe by title seems a easy question, but I didn´t know how to do the shortest title for my question.
I want to delete elements from array on javascript, yes, but what I am looking for exactly is delete from array mismatched elements with other array on javascript (maybe it could be title, but too large).
For example:

Array A=> [a, b, c, d]
Array B=> [b,d]
Array C = deleteMismatchedElements(A,B)
Array C (after function)-> [b,d]

I suppose that using a nested foreach loop it could be possible, but I wonder if there is a better way, something as a "native" implemented method that could be called, or similar...

Thank you very much.

解决方案

var C = [];
for(var i = 0; i < B.length; i ++){
    if(A.indexOf(B[i]) > -1){
        C.push(B[i]);
    }
}

What this does is

1. Creates array C
2. Runs through each item in B
3. if B[i] is in A, add it to C

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