问题描述
我得到一个例外JSON工作时。我的JSON preSR类是如下
I am getting a exception while working in json . My JSONPresr class is as follow
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
import android.os.AsyncTask;
import android.util.Log;
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
public JSONObject getJSONFromUrl(String url) {
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "UTF-8"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
System.out.println(" value in json sting"+json);
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
Log.e("JSON Parser", "Error parsing data [" + e.getMessage()+"] "+json);
System.out.println(" error is here");
}
// return JSON String
return jObj;
}
}
我对这些code让我的数据
I am getting my data by these code
String TAG_user_detail = "user_details";
String TAG_user_id = "user_id";
String TAG_user_name = "user_name";
String TAG_user_phone = "user_phone";
String TAG_ref_id = "ref_id";
JSONArray user_detail_jsonarray = null;
JSONParser jParser = new JSONParser();
// getting JSON string from URL
JSONObject json = jParser.getJSONFromUrl(url);
try {
// Getting Array of Contacts
user_detail_jsonarray = json.getJSONArray(TAG_user_detail);
// looping through All Contacts
for(int i = 0; i < user_detail_jsonarray.length(); i++){
JSONObject c = user_detail_jsonarray.getJSONObject(i);
// Storing each json item in variable
int id = c.getInt(TAG_user_id);
System.out.println("user id from json"+id);
String name_fromjson = c.getString(TAG_user_name);
System.out.println("user name from json"+name_fromjson);
int phone_no_fromjson = c.getInt(TAG_user_phone);
System.out.println("user phone from json"+phone_no_fromjson);
int ref_id_fromjson = c.getInt(TAG_ref_id);
System.out.println("user ref id from json"+ref_id_fromjson);
}
} catch (JSONException e) {
e.printStackTrace();
}
但我countiniously得到异常在这一行
But i am countiniously getting Exception in this line
user_detail_jsonarray = json.getJSONArray(TAG_user_detail);
我赌注跟踪消息为
My Stake Trace message is as
{"ref_id":1295,"user_name":"chand","user_phone":"9620085675","user_id":"1"} at user_details of type org.json.JSONObject cannot be converted to JSONArray
我试了很多联系,但遗憾的是我不能够让我的结果。请任何机构只是帮助我解决这个问题。在此先感谢所有
I tried many link but unfortunately i am not able to get my result. Please any body just help me to solve this issue. Thanks in advance to all
推荐答案
它明确从您正试图转换JSON对象成JSON数组错误。这不应该。
Its clear from error that you are trying to convert Json Object into Json array. That should not.
下面是code读你的JSON响应。
Here is the code to read your JSON response.
String json = "Assuming that here is your JSON response";
try {
JSONObject parentObject = new JSONObject(json);
JSONObject userDetails = parentObject.getJSONObject("user_details");
//And then read attributes like
String name = userDetails.getString("user_name");
String phone = userDetails.getString("user_phone");
String id = userDetails.getString("ref_id");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
以上code是<$c$c>{"user_details":{"user_id":"1","user_name":"chand","user_phone":"9620085675","ref_id":6386}}$c$c> JSON。
这篇关于org.json.JSONObject不能转换为JSONArray的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!