字符串不支持[]运算符

本文介绍了字符串不支持[]运算符的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 对于此代码，我得到了错误。在此行 $ sname [] = $ rs ['StudentId']; PHP致命错误：[]字符串不支持运算符$ sname = array（）; $ i = 0;For this code i get the error.at this line $sname[] = $rs['StudentId'];PHP Fatal error: [] operator not supported for strings $sname = array(); $i=0;foreach($data as $rs){ foreach($SchoolName as $sname){// echo $rs['SchoolName'].'=='.$sname."<br />"; echo $i."<br />"; if($rs['SchoolName'] == $sname){ $sname[] = $rs['StudentId']; } $i++; }}推荐答案 工作演示$SchoolNames = Array(10003, "Southwestern College", "National University", "Western Governors University", "Southwestern College Admissions Center - Evaluations Dept");$data = array( 0 => Array( 'STU_MANG_fname' => "Jennifer", 'STU_MANG_lname' => "patel", 'SchoolName' => "Southwestern College Admissions Center - Evaluations Dept", 'ShipAddress1' => "900 Otay Lakes Road", 'ShipState' => "CALIFORNIA" ));foreach($data as $studen_info){ foreach($SchoolNames as $id=>$school_name){ if($studen_info['SchoolName'] == $school_name){ $student_names[$school_name] = $id; //$student_names[$school_name] = $student_info['StudentId'];; } }}print_r($student_names);您给我的学生信息数组中没有'StudentId'，所以我假设您想使用学生数组的键（如果实际上我已经注释掉了'StudentId'使用行）there was no 'StudentId' in the student info array you gave me so I assume you want to use the key of the student array if there is in fact a 'StudentId' use line i commented out 这篇关于字符串不支持[]运算符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！