问题描述
我是一名大学生.现在，我正在做一个必须使用 LDAP 连接来验证登录过程中用户的用户名和密码的项目.所以，我的网站是使用 JSP 开发的.我试图解决代码错误，但我不能.我是不是搞错了?
I'm a college student. Now, i'm doing a project that must use LDAP connection to authenticate the username and password of the user in log in process. So, my website is develop by use JSP. I try to solve the error of code but i can't. Did I makes some mistake on it?
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@ page import="java.util.*" %>
<%@ page import="javax.naming.*" %>
<%@ page import="java.util.regex.*" %>
<%@ page import="javax.naming.directory.*" %>
<%@ page import="java.util.Hashtable.*" %>
<%@ page import="javax.naming.ldap.*" %>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
<%
String username = request.getParameter("email");
String password = request.getParameter("password");
Hashtable<String, String> env = new Hashtable<String, String>();
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, "ldap://ldap-pj.sit.kmutt.ac.th");
env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, username);
env.put(Context.SECURITY_CREDENTIALS, password);
try {
//Connect with ldap
new InitialLdapContext(env, null);
//Connection succeeded
System.out.println("Connection succeeded!");
} catch (AuthenticationException e) {
//Connection failed
System.out.println("Connection failed!");
e.printStackTrace();
}
%>
</body>
</html>
我在运行代码时收到此错误消息.
and I got this error msg from running the code.
HTTP 状态 500 -
输入异常报告
消息
描述服务器遇到一个内部错误()阻止它无法满足此请求.
description The server encountered an internal error () that prevented it from fulfilling this request.
异常
org.apache.jasper.JasperException:发生异常处理JSP 页面/ldap_checking.jsp 在第 33 行
org.apache.jasper.JasperException: An exception occurred processing JSP page /ldap_checking.jsp at line 33
30: 31: try { 32://连接 ldap 33: newInitialLdapContext(env, null);34:35://连接成功36:System.out.println("连接成功！");
30: 31: try { 32: //Connect with ldap 33: new InitialLdapContext(env, null); 34: 35: //Connection succeeded 36: System.out.println("Connection succeeded!");
堆栈跟踪:org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568)org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:455)org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 根原因
Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:455) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) root cause
javax.servlet.ServletException:javax.naming.InvalidNameException:[LDAP:错误代码 34 - 无效的 DN]org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:911)org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:840)org.apache.jsp.ldap_005fchecking_jsp._jspService(ldap_005fchecking_jsp.java:212)org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)javax.servlet.http.HttpServlet.service(HttpServlet.java:722)org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 根原因
javax.servlet.ServletException: javax.naming.InvalidNameException: [LDAP: error code 34 - invalid DN] org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:911) org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:840) org.apache.jsp.ldap_005fchecking_jsp._jspService(ldap_005fchecking_jsp.java:212) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) root cause
javax.naming.InvalidNameException:[LDAP:错误代码 34 - 无效 DN]com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:3028)com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:2835)com.sun.jndi.ldap.LdapCtx.connect(LdapCtx.java:2749)com.sun.jndi.ldap.LdapCtx.(LdapCtx.java:316)com.sun.jndi.ldap.LdapCtxFactory.getUsingURL(LdapCtxFactory.java:193)com.sun.jndi.ldap.LdapCtxFactory.getUsingURLs(LdapCtxFactory.java:211)com.sun.jndi.ldap.LdapCtxFactory.getLdapCtxInstance(LdapCtxFactory.java:154)com.sun.jndi.ldap.LdapCtxFactory.getInitialContext(LdapCtxFactory.java:84)javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:684)javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:307)javax.naming.InitialContext.init(InitialContext.java:242)javax.naming.ldap.InitialLdapContext.(InitialLdapContext.java:153)org.apache.jsp.ldap_005fchecking_jsp._jspService(ldap_005fchecking_jsp.java:97)org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)javax.servlet.http.HttpServlet.service(HttpServlet.java:722)org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 注意Apache 中提供了根本原因的完整堆栈跟踪Tomcat/7.0.27 日志.
javax.naming.InvalidNameException: [LDAP: error code 34 - invalid DN] com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:3028) com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:2835) com.sun.jndi.ldap.LdapCtx.connect(LdapCtx.java:2749) com.sun.jndi.ldap.LdapCtx.(LdapCtx.java:316) com.sun.jndi.ldap.LdapCtxFactory.getUsingURL(LdapCtxFactory.java:193) com.sun.jndi.ldap.LdapCtxFactory.getUsingURLs(LdapCtxFactory.java:211) com.sun.jndi.ldap.LdapCtxFactory.getLdapCtxInstance(LdapCtxFactory.java:154) com.sun.jndi.ldap.LdapCtxFactory.getInitialContext(LdapCtxFactory.java:84) javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:684) javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:307) javax.naming.InitialContext.init(InitialContext.java:242) javax.naming.ldap.InitialLdapContext.(InitialLdapContext.java:153) org.apache.jsp.ldap_005fchecking_jsp._jspService(ldap_005fchecking_jsp.java:97) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) note The full stack trace of the root cause is available in the Apache Tomcat/7.0.27 logs.
Apache Tomcat/7.0.27
Apache Tomcat/7.0.27
推荐答案
这是重要的一行:javax.naming.InvalidNameException:[LDAP:错误代码 34 - 无效 DN]
This is the important line: javax.naming.InvalidNameException: [LDAP: error code 34 - invalid DN]
你可以看这里:https://wiki.servicenow.com/index.php?title=LDAP_Error_Codes
对于 34 的含义，但您尝试使用的专有名称看起来不正确.看起来您的主体可能格式不正确.请参阅 oracle 的本指南进行 ldap 身份验证:http://docs.oracle.com/javase/jndi/tutorial/ldap/security/ldap.html
for what 34 means, but it looks like the distinguished name you are trying to use is incorrect. It looks like your principal could be formatted incorrectly. See this guide from oracle on doing ldap authentication:http://docs.oracle.com/javase/jndi/tutorial/ldap/security/ldap.html
特别注意他们设置环境条目的这一部分:
pay special attention to this part of it where they set up the environment entries:
env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, "cn=S. User, ou=NewHires, o=JNDITutorial");
env.put(Context.SECURITY_CREDENTIALS, "mysecret");
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