如何在本地时区中将javax.time.Instant格式化为字符串？

问题描述

如何格式化作为本地时区的字符串？以下将本地 Instant 转换为 ，而不是我所期望的当地时区。将呼叫删除到也是一样的。如何获取当地时间？

How do I format a javax.time.Instant as a string in the local time zone? The following translates a local Instant to UTC, not to the local time zone as I was expecting. Removing the call to toLocalDateTime() does the same. How can I get the local time instead?

public String getDateTimeString( final Instant instant )
{
    checkNotNull( instant );
    DateTimeFormatterBuilder builder = new DateTimeFormatterBuilder();
    DateTimeFormatter formatter = builder.appendPattern( "yyyyMMddHHmmss" ).toFormatter();
    return formatter.print( ZonedDateTime.ofInstant( instant, TimeZone.UTC ).toLocalDateTime() );
}

注意：我们使用的是旧版本的参考实施。

Note: We're using the older version 0.6.3 of the JSR-310 reference implementation.

推荐答案

在您投票之前，我的回答请注意，问题明确（和粗体字）是指旧版本> 0.6.3 的JSR-310参考实现！我在2012年12月问到这个问题，早在Java 8和新的日期库到来之前！

Before you down vote my answer, please note that the question explicitly (and in bold typeface) refers to old version 0.6.3 of the JSR-310 reference implementation! I asked this question in December 2012, long before the arrival of Java 8 and the new date library!

我放弃了JSR-310课程 DateTimeFormatter 和 ZonedDateTime 而不是使用旧式的 java.util.Date 和 java.text.SimpleDateFormat ：

I gave up on JSR-310 classes DateTimeFormatter and ZonedDateTime and instead resorted to old fashioned java.util.Date and java.text.SimpleDateFormat:

public String getDateTimeString( final Instant instant )
{
    checkNotNull( instant );
    DateFormat format = new SimpleDateFormat( "yyyyMMddHHmmss" );
    Date date = new Date( instant.toEpochMillisLong() );
    return format.format( date );
}

这篇关于如何在本地时区中将javax.time.Instant格式化为字符串？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！