Spreadsheets中使用名称而不是字母来选择列

Spreadsheets中使用名称而不是字母来选择列

本文介绍了在Google Spreadsheets中使用名称而不是字母来选择列,而不是字母?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

新手问题,当将Google查询语言与Google Spreadsheets结合使用时,是否可以按名称而不是字母来选择列?

newbie question, is it possible to select columns by name rather than letter when using Google Query Language with Google Spreadsheets?

这对我来说很好:"SELECT A,COUNT(B)GROUP BY A"

This works fine for me: "SELECT A, COUNT(B) GROUP BY A"

如果我可以在第一行中使用列标题,就像在数据库中那样,那就太好了,

It'd be great if I could use the column headers in the first row, more like a database, as in:

选择学生,按学生计数(拘留)的GROUP"

"SELECT student, COUNT(detention) GROUP BY student"

我怀疑这是不可能的,但是希望这又是我的Internet搜索技能使我失败的另一种情况.

I suspect it's not possible, but hope this yet another case where my Internet search skills failed me.

推荐答案

目前无法实现. GQL文档指出[1]列是由标识符(而不是标签)引用的.例如,在Google Spreadsheet中,列标识符是一或两个字符的列字母(A,B,C,...). "

This is currently not possible. The GQL documentation states[1] "Columns are referenced by the identifiers (not by labels). For example, in a Google Spreadsheet, column identifiers are the one or two character column letter (A, B, C, ...)."

如果要在电子表格中执行此操作,则可以使用以下公式将列标题名称转换为字母(可能需要+1进行一些调整(可能为+2)).它还依赖于列标题的唯一性,并且不包含逗号

If you want to do this in a spreadsheet it is possible with the following formula to convert a column header name into a letter (some tweaking might be required +1 (might be +2)). It also relies on column headers being unique and not containing commas

=REGEXEXTRACT(ADDRESS(1,COUNTA(SPLIT(LEFT(JOIN(",",TRANSPOSE(1:1)),FIND("your_column_name",JOIN(",",TRANSPOSE(1:1)))),","))+1,4);"[a-zA-Z]+")

[1] https://developers.google.com/chart/interactive /docs/querylanguage#Select

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07-30 17:32