来自 文档,-sendEvent: 方法:讨论如果需要,可以通过以下方式拦截传入的事件子类化 UIApplication 并覆盖此方法.对于每个事件你拦截,你必须通过调用[super sendEvent:event]来调度它在您的实现中处理事件之后.所以,它看起来像这样:CustomUIApplication.h:@interface CustomUIApplication:UIApplication- (void)sendEvent:(UIEvent *)event;@结尾CustomUIApplication.m:@implementation CustomUIApplication- (void)sendEvent:(UIEvent *)event{//...做你的事...[超级发送事件:事件];}@结尾当然,您需要确保使用您的子类而不是默认的UIApplication.这是关于如何在 Objective-C 中执行此操作的 Stack Overflow 答案,以及 这里是 Swift.Is it possible to intercept all user actions like tap, swipe, enter text, etc. on all windows of my app? 解决方案 Like I said in the comments, subclass UIApplication and override the instance method sendEvent:.From the documentation for the UIApplication class, -sendEvent: method: Discussion If you require it, you can intercept incoming events by subclassing UIApplication and overriding this method. For every event you intercept, you must dispatch it by calling [super sendEvent:event] after handling the event in your implementation.So, it would look like this:CustomUIApplication.h:@interface CustomUIApplication:UIApplication- (void)sendEvent:(UIEvent *)event;@endCustomUIApplication.m:@implementation CustomUIApplication- (void)sendEvent:(UIEvent *)event{ // ...Do your thing... [super sendEvent:event];}@endOf course, you need to make sure your subclass is used instead of the default UIApplication. Here is a Stack Overflow answer on how to do it in Objective-C, and here in Swift. 这篇关于目标 C:是否可以通过一个类拦截所有用户操作?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 10-20 12:19