Python 脚本没有列出目录中的文件?

问题描述

我有一个小问题.

我有以下功能:

def getCommands():
    for file in os.listdir(com_dir):
        if file.endswith(com_ext):
            z = string.strip(file, '.gcom')
            print z

并且在目录(由 com_dir 定义)中有三个文件.

and in the directory ( Defined by com_dir ) there are three files.

a.gcomb.gcomc.gcom

运行时getCommands()

输出如下:

明智的变量.

Files a and b are shown ,however, c is not shown, All files are in the directory and all are using the same file extension: .gcom which is also com_ext variable wise.

有人对为什么文件 c 没有显示有任何提示吗?

Does anyone have any hints as to why file c is not being shown?

旁注:输出中似乎有一个空格，其中 c 应该是但是我不确定这是否与手头的问题有任何关系，而不仅仅是一个偶然的空间放置在脚本的其他位置.

Side note: There seems to be a blank space in the output where c should be however Im not sure if this has any part in the issue at hand and isn't just simply a accidental space placed elsewhere in the script.

推荐答案

strip 从字符串的两端删除所有给定的字符，无论它们出现的顺序如何.如果您的字符串是 c.gcom，然后 strip('.gcom') 删除所有字符 ., g, c, o 和 m 从你的字符串的末尾，不留下任何东西.它不会停止剥离，直到遇到一个不是 .、g、c、o 或m(或删除所有内容).

strip removes all the given characters from both ends of your string, whatever order they occur in. If your string is c.gcom, then strip('.gcom') removes all the characters ., g, c, o and m from the ends of your string, leaving nothing left. It doesn't stop stripping until it hits a character that is not ., g, c, o or m (or removes everything).

如果您有一个以 .gcom 结尾的字符串，而您只想删除该结尾，您可以使用:

If you have a string ending in .gcom, and you just want to remove that ending, you can use:

z = file[:-5]

或者，使用您的 com_ext 变量

or, using your com_ext variable

com_ext = '.gcom'
...
if file.endswith(com_ext):
    z = file[:-len(com_ext)]

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