问题描述
我想将aphostrophe的值分配给char：
I want to assign the value of aphostrophe to a char:
char a = '\'';
但是我想使用untropode版本的撇号（\ u0027）来保持一致我的代码：
However I would like to use the unicode version of apostrophe (\u0027) to keep it consistent with my code:
char a = '\u0027';
但这样做会产生错误，说未关闭的字符文字。
But doing it this way gives an error saying "unclosed character literal".
如果在代码中仍然使用unicode代码，我该怎么做呢？
How can I do this assignment while still having the unicode code in the code?
推荐答案
\\\' 不起作用的原因是编译器非常早地处理unicode转义，当然，它最终成为  —它终止了文字。编译器实际上看到了这一点：
The reason \u0027 doesn't work is that the unicode escape is handled very early by the compiler, and of course, it ends up being ' — which terminates the literal. The compiler actually sees this:
char a = ''';
......这自然是个问题。 JLS在关于换行的内容中讨论了这一点，如（字符文字）。
...which naturally is a problem. The JLS talks about this in relation to line feeds and such in §3.10.4 (Character Literals).
坦率地说，我认为你是最好的写作
Frankly, I think you're best off writing
char a = '\'';
...但 char 是一个数字类型，所以你可以这样做：
...but char is a numeric type, so you could do this:
char a = 0x0027;
当然，你可以这样做：
char a = "\u0027".charAt(0);
...但我认为我们都同意这有点矫枉过正。 ; - ）
...but I think we can all agree that's a bit overkill. ;-)
哦，或查看： char a ='\ u005c \ u0027'; （ \ u005c 当然是反斜杠 —所以编译器看到'\''）。
Oooh, or check out Greg's answer: char a = '\u005c\u0027'; (\u005c is, of course, a backslash — so the compiler sees '\'').
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