从字符串转换为枚举用C

问题描述

有没有采取一个字符串（由用户输入），并将其转换为枚举值convienent的方式？在这种情况下，该字符串将枚举值的名称，例如：

Is there a convienent way to take a string (input by user) and convert it to an Enumeration value? In this case, the string would be the name of the enumeration value, like so:

enum Day
{
    Sunday = 0,
    Monday = 1,
    ...
}

因此​​，如果用户给一个日的名称，就能够解析为相应的枚举值

So that if the user gave the name of a Day, it would be able to parse that to the corresponding Enum value.

诀窍是，我有超过500个值我的工作，他们正穿过多个枚举$ P $垫出来。

The trick is, I have over 500 values I'm working with, and they are spread out across multiple enumerations.

我知道在C＃中Enum.Parse方法，所以有在C某种形式的吗？

I know of the Enum.Parse Method in c#, so is there some form of this in c?

推荐答案

要实现它的标准方式是沿着线的东西：

The standard way to implement it is something along the lines of:

typedef enum {value1, value2, value3, (...) } VALUE;

const static struct {
    VALUE      val;
    const char *str;
} conversion [] = {
    {value1, "value1"},
    {value2, "value2"},
    {value3, "value3"},
       (...)
};

VALUE
str2enum (const char *str)
{
     int j;
     for (j = 0;  j < sizeof (conversion) / sizeof (conversion[0]);  ++j)
         if (!strcmp (str, conversion[j].str))
             return conversion[j].val;
     error_message ("no such string");
}

相反的应该是显而易见的。

The converse should be apparent.

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