本文介绍了如何让我的“prev”和“下一个”按钮工作分页?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
< script src =https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js>< / script>< link href =https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css =stylesheet/>< nav> < ul class =pagination> <李> < a href =#aria-label =上一个> < span aria-hidden =true>& laquo;< / span> < / A> < /锂> < li>< a href =#> 1< / a>< / li> < li>< a href =#> 2< / a>< / li> < li>< a href =#> 3< / a>< / li> < li>< a href =#> 4< / a>< / li> < li>< a href =#> 5< / a>< / li> <李> < a href =#aria-label =下一个> < span aria-hidden =true>& raquo;< / span> < / A> < /锂> < / nav>
然而,prev和下一步按钮也将激活。
当我点击prev或next按钮,而不是将active添加到prev和next按钮时,我可以做些什么来只切换页面active。
解决方案向前一个和下一个按钮添加一个类,即您的案例中的列表项,并使用
.not()$ c $
$(document).ready(function(){var pageItem = $(。pagination li)。 not(。prev,.next); var prev = $(。pagination li.prev); var next = $(。pagination li.next); pageItem.click(function(){pageItem.removeClass (active); $(this).not(.prev,.next).addClass(active);}); next.click(function(){$('li.active')。removeClass ('active')。next()。addClass('active');}); prev.click(function(){$('li.active')。removeClass('active')。prev()。addClass( 'active');});});
< script src =https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js >< / script>< link href =https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.cssrel =stylesheet/>< nav> < ul class =pagination> < li class =prev> < a href =#aria-label =上一个> < span aria-hidden =true>& laquo;< / span> < / A> < /锂> < li>< a href =#> 1< / a> < /锂> < li>< a href =#> 2< / a> < /锂> < li>< a href =#> 3< / a> < /锂> < li>< a href =#> 4< / a> < /锂> < li>< a href =#> 5< / a> < /锂> < li class =next> < a href =#aria-label =下一个> < span aria-hidden =true>& raquo;< / span> < / A> < /锂> < / nav>
$(document).ready(function(){
var $pageItem = $(".pagination li")
$pageItem.click(function(){
$pageItem.removeClass("active");
$(this).addClass("active");
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" rel="stylesheet"/>
<nav>
<ul class="pagination">
<li>
<a href="#" aria-label="Previous">
<span aria-hidden="true">«</span>
</a>
</li>
<li><a href="#">1</a></li>
<li><a href="#">2</a></li>
<li><a href="#">3</a></li>
<li><a href="#">4</a></li>
<li><a href="#">5</a></li>
<li>
<a href="#" aria-label="Next">
<span aria-hidden="true">»</span>
</a>
</li>
</ul>
</nav>
Now, I am using bootstrap pagination and add some customise feature using jQuery to make page "active" when I click on it which mean current page.
However, the "prev" and "next" button will be also "active".What can I do to only switch page "active" when click on "prev" or "next" button and not to add "active" to "prev" and "next" button.
解决方案 Add a class to the previous and next buttons i.e. list items in your case and use .not()
to exclude them.
$(document).ready(function() {
var pageItem = $(".pagination li").not(".prev,.next");
var prev = $(".pagination li.prev");
var next = $(".pagination li.next");
pageItem.click(function() {
pageItem.removeClass("active");
$(this).not(".prev,.next").addClass("active");
});
next.click(function() {
$('li.active').removeClass('active').next().addClass('active');
});
prev.click(function() {
$('li.active').removeClass('active').prev().addClass('active');
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" rel="stylesheet" />
<nav>
<ul class="pagination">
<li class="prev">
<a href="#" aria-label="Previous">
<span aria-hidden="true">«</span>
</a>
</li>
<li><a href="#">1</a>
</li>
<li><a href="#">2</a>
</li>
<li><a href="#">3</a>
</li>
<li><a href="#">4</a>
</li>
<li><a href="#">5</a>
</li>
<li class="next">
<a href="#" aria-label="Next">
<span aria-hidden="true">»</span>
</a>
</li>
</ul>
</nav>
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08-19 09:03