问题描述
我试图找出如何获取整数列表并将该列表中的所有项目返回到另一个列表作为其最大值，但是使用它们的索引。
I'm trying to figure out how I can take a list of integers and return all the items in that list into another list as their max value, but with their index.
所以我需要能够在不使用枚举，lambda，numpy或任何类似的东西的情况下执行此操作。它必须是列表的基本方法。基本上，像append，max等。 。
如果声明也很好。
So I need to be able to do this without using enumeration, lambda, numpy, or anything of that sort. It has to be really basic methods for lists. Basically, things like append, max, etc. . .If for statements are fine too.
为了澄清我想要做的事情，请说我有一个清单： [4,34,0,0,6,34， 1]
我希望它返回 [1,5]
To clarify what I'm trying to do, say I have a list: [4, 34, 0, 0, 6, 34, 1]I want it to return [1, 5]
推荐答案
最简单的方法：
in [24]: a = [4, 34, 0, 0, 6, 34, 1]
In [25]: j=0
In [26]: M=[]
In [27]: m = max(a)
In [28]: for i in a:
if i==m:
M.append(j)
j+=1
....:
In [29]: M
Out[29]: [1, 5]
使用list-comprehension和enumerate，上面的内容可缩短为：
Using list-comprehension and enumerate, the above can be shortened to:
In [30]: [i for i, x in enumerate(a) if x == max(a)]
Out[30]: [1, 5]
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