本文介绍了按任意Lambda排序的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
如何通过任意函数描述的键对列表进行排序?例如，如果我有:
How can I sort a list by a key described by an arbitrary function? For example, if I have:
mylist = [["quux", 1, "a"], ["bar", 0, "b"]]
我想按每个成员的第二个元素对"mylist"进行排序，例如
I'd like to sort "mylist" by the second element of each member, e.g.
sort(mylist, key=lambda x: x[1])
我该怎么做?
推荐答案
您基本上已经拥有它:
>>> mylist = [["quux", 1, "a"], ["bar", 0, "b"]]
>>> mylist.sort(key=lambda x: x[1])
>>> print mylist
给予:
[['bar', 0, 'b'], ['quux', 1, 'a']]
这将对mylist进行排序.
That will sort mylist in place.
[由于@Daniel的更正，此段进行了编辑.] sorted将返回已排序的新列表，而不是实际更改输入，如 http://wiki.python.org/moin/HowTo/Sorting/.
[this para edited thanks to @Daniel's correction.] sorted will return a new list that is sorted rather than actually changing the input, as described in http://wiki.python.org/moin/HowTo/Sorting/.
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