使用带有Java的Selenium WebDriver检查元素不存在的最佳方法

问题描述

我正在尝试下面的代码，但似乎无法正常工作.有人可以向我展示最佳方法吗?

Im trying the code below but it seems it does not work... Can someone show me the best way to do this?

public void verifyThatCommentDeleted(final String text) throws Exception {
    new WebDriverWait(driver, 5).until(new ExpectedCondition<Boolean>() {
            @Override
            public Boolean apply(WebDriver input) {
                try {
                    input.findElement(By.xpath(String.format(
                            Locators.CHECK_TEXT_IN_FIRST_STATUS_BOX, text)));
                    return false;
                } catch (NoSuchElementException e) {
                    return true;
                }
            }
        });
    }

推荐答案

我通常使用两种方法(成对使用)来验证元素是否存在:

i usually couple of methods (in pair) for verification whether element is present or not:

public boolean isElementPresent(By locatorKey) {
    try {
        driver.findElement(locatorKey);
        return true;
    } catch (org.openqa.selenium.NoSuchElementException e) {
        return false;
    }
}

public boolean isElementVisible(String cssLocator){
    return driver.findElement(By.cssSelector(cssLocator)).isDisplayed();
}

请注意，有时硒可以在DOM中找到元素，但是它们是不可见的，因此硒将无法与其交互.因此，在这种情况下，检查可见性的方法会有所帮助.

Note that sometimes selenium can find elements in DOM but they can be invisible, consequently selenium will not be able to interact with them. So in this case method checking for visibility helps.

如果要等待元素出现，直到我发现最好的解决方案是使用流畅的等待:

If you want to wait for the element until it appears the best solution i found is to use fluent wait:

public WebElement fluentWait(final By locator){
    Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
            .withTimeout(30, TimeUnit.SECONDS)
            .pollingEvery(5, TimeUnit.SECONDS)
            .ignoring(NoSuchElementException.class);

    WebElement foo = wait.until(new Function<WebDriver, WebElement>() {
        public WebElement apply(WebDriver driver) {
            return driver.findElement(locator);
        }
    });

    return foo;
};

希望这会有所帮助)

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