[解决]正则表达式字符串拆分c＃

问题描述

嗨专家，

Hi experts,

string Input = "@a = '1', @b = '[email protected],[email protected]'"

我想拆分输入字符串并希望输出如下使用正则表达式

I want to split Input string and want output as below using regex

ary[0] = a = '1'
ary[1] = b = '[email protected]'

我希望用@和它分开不应该用单引号

感谢adv。

I want to split by @ and it should not be in single quotes
thanks in adv.

推荐答案

string Input = "@a = '1', @b = '[email protected],[email protected]'"
string[] ary = Input.Split(',');

string Input = "@a = '1', @b = '[email protected],[email protected]'"
string Output = Regex.Split(Input, @"(?=@\w+[ =|=])@")

（条件）true | false

(condition)true|false

(?=@\w+[ =|=]) condition
@              if true then split by @


--condition work as below

?         In supplied input What
=         is equal to
@\w+      a(single) word that start with @
[ =|=]    and after the word end it contain space+= or =

快乐编码！

：）

Happy Coding!
:)

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