本文介绍了MySQL加入最大值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

通过加入entry.id上的下表,我想从food_brands表中提取具有最高type_id的行-因此,我应该以type_id 11940获得下面的前3行

From joining the tables below on the entry.id, I want to extract the rows from the food_brands table which have the highest type_id - so I should be getting the top 3 rows below, with type_id 11940

food_brands

food_brands

        id      brand       type_id
        15375   cesar       11940
        15374   brunos      11940
        15373   butchers    11940
        15372   bakers      11939
        15371   asda        11939
        15370   aldi        11939

类型

        id      type      quantity      food_id
        11940   comm      53453         10497
        11939   comm      999           10496

食物

        id      frequency   entry_id
        10497   twice       12230
        10496   twice       12230
        10495   once        12230

条目

         id     number
         12230  26

我对查询的尝试并未过滤掉较低的type.id记录-因此,从下面food_brands中的表记录中,我得到了type_id 11940和11939的表.感谢您为解决此问题提供了帮助! >

My attempt at the query isn't filtering out the lower type.id records - so from the table records below in food_brands, i'm getting those with type_id 11940 and 11939. Grateful for any help fix this!

SELECT fb.*
                        FROM food_brands fb
                        INNER JOIN types t ON fb.type_id = t.id
                        INNER JOIN
                        (
                            SELECT MAX(id) AS MaxID
                            FROM types
                            GROUP BY id
                        ) t2 ON t.food_id = t2.food_id AND t.id = t2.MaxID
                        INNER JOIN foods f ON t.food_id = f.id
                        INNER JOIN entries e ON f.entry_id = e.id
                        WHERE entries.id = 12230

推荐答案

一个简单的子查询就可以了;

A simple subquery should do it just fine;

SELECT * FROM food_brands WHERE type_id=
  (SELECT MAX(t.id) tid FROM types t
   JOIN foods f ON f.id=t.food_id AND f.entry_id=12230)

要测试的SQLfiddle .

这篇关于MySQL加入最大值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-30 10:14