本文介绍了不能下标'[NSObject:AnyObject]类型的值吗?索引类型为'String'的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

错误:

代码:

  func getApple(appleId: String) {
     var apples = userDefaults.dictionaryForKey("apples_array")
     println(apples[appleId])


推荐答案

应该是:

var apples = userDefaults.dictionaryForKey("apples_array")
println(apples?[appleId])

这里的问题是类型 [NSObject:AnyObject]?意味着一个可选类型,这意味着你试图调用一个基本上是enum的下标。当你尝试这样做时,没有声明下标,所以系统会窒息。

The issue here is that type [NSObject : AnyObject]? implies an optional type, which means you're attempting to call a subscript on what is essentially an enum. When you try to do this, there's no subscript declared, so the system chokes.

通过添加我们如果可能的话,打开这个值,然后调用下标。通过这种方式,系统可以查看类型 [NSObject:AnyObject] 以获取下标声明,一切正常。

By adding the ? we're saying, unwrap this value if possible, and then call the subscript. This way the system infers to look on type [NSObject : AnyObject] for subscript declarations and everything is ok.

您也可以使用强制解包,但如果 apples 为nil,则会崩溃。另一种可能的方法是:

You could also use ! to force an unwrap, but this will crash if apples is nil. Another possible way to write this would be:

let apples = userDefaults.dictionaryForKey("apples_array") ?? [:]
println(apples[appleId])

这样,苹果就不再了可选,它将始终具有下标语法。不需要打包。

This way, apples is no longer optional and it will always have the subscript syntax. No unwrapping necessary.

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07-30 08:14