copy()函数的第二个参数不能是目录

问题描述

任何人都知道为什么:

<?PHP
$title = trim($_POST['title']);
$description = trim($_POST['description']);

// Array of allowed image file formats
$allowedExtensions = array('jpeg', 'jpg', 'jfif', 'png', 'gif', 'bmp');

foreach ($_FILES as $file) {
  if ($file['tmp_name'] > '') {
    if (!in_array(end(explode(".",
            strtolower($file['name']))),
            $allowedExtensions)) {
      echo '<div class="error">Invalid file type.</div>';
    }
  }
}

if (strlen($title) < 3)
  echo '<div class="error">Too short title</div>';
else if (strlen($description) > 70)
  echo '<div class="error">Too long desccription.</div>';

else {
  move_uploaded_file($_FILES['userfile']['tmp_name'], 'c:\wamp\www\uploads\images/');
}

赠予:

推荐答案

这是因为您正在移动文件，并且认为您正在尝试将该文件重命名为第二个参数(在本例中为Director).

It's because you're moving a file and it thinks you're trying to rename that file to the second parameter (in this case a director).

应为:

move_uploaded_file($_FILES['userfile']['tmp_name'], 'c:/wamp/www/uploads/images/'.$file['name']);

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