本文介绍了如何在ggplot2中绘制xts?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我得到了这个情节
使用此代码
library(xts)
library(zoo)
plot.new()
par(mai=c(2, 2, 1, 1))
plot(nats[,2], ylim=c(0, 2.5),
xlab = "", ylab="", main="", major.ticks="months",
major.format="%d-%b-%Y", minor.ticks=FALSE, las=1, cex.axis=0.8)
points(nats[rans,2], col="darkgrey", pch=16, cex=0.5)
points(M1[rans], col="red", pch=16, cex=0.5)
points(M2[rans], col="blue", pch=16, cex=0.5)
points(M3[rans], col="green", pch=16, cex=0.5)
legend(x="topright",
legend=c("a", "Actual value", "M1","M2","M3"),
col=c("Black", "Grey", "Red","Blue","Green"),
lwd=1, lty=c(1,NA,NA,NA, NA),
pch=c(NA,16,16,16,16), merge=FALSE, cex=0.6)
数据
set.seed(123)
date <- as.Date(seq(as.Date("2003-01-01"),
as.Date("2003-05-31"), by = 1), format="%Y-%m-%d")
a <- runif(151, 0.005, 2.3)
df <- data.frame(date, a)
#select 30 random samples
rans<-sample(length(df$a), 30)
df$a.rm <- df$a
#set the values for the selected rows as NA
df[rans, 3]<-NA
#reorder columns
df <- subset(df, select=c(1,3,2))
# test 3 methods for filling NA
nats<-xts(df[,-1], as.POSIXct(df$date))
M1<-na.locf.default(nats[,1])
M2<-na.approx(nats[,1])
M3<-na.spline(nats[,1])
任何建议如何使用 ggplot2
进行绘制的建议将不胜感激?
Any suggestion how to plot it using ggplot2
will be appreciated?
推荐答案
感谢,我使用 fortify()
函数使用 ggplot2
创建了上面的图>
Thanks to @jlhoward's answer, I used fortify()
function to create the plot above using ggplot2
library(ggplot2)
nats1 <- fortify(nats)
M1.1 <- fortify(M1)
M2.2 <- fortify(M2)
M3.3 <- fortify(M3)
cols <- c("a"="black", "Actual value" = "black","M1"="red","M2"="blue", "M3" = "green")
ggplot(data=nats1, aes(x=Index, y=a))+
geom_line(aes())+
geom_point(data=nats1[rans,], aes(x=Index, y=a, color="Actual value"), size=2)+
geom_point(data=M1.1[rans,], aes(x=Index, y=a.rm, color="M1"), size=2)+
geom_point(data=M2.2[rans,], aes(x=Index, y=a.rm, color="M2"), size=2)+
geom_point(data=M3.3[rans,], aes(x=Index, y=a.rm, color="M3"), size=2)+
scale_colour_manual(name=" ", values=cols)
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