JQuery - 获取选择值

问题描述

我正在尝试通过 jQuery 从下拉列表中获取选定的值.我有一些 javascript 在我点击发送时验证表单，以确保没有空格，代码如下:

I'm trying to get the selected value from a drop down list via jQuery. I have a bit of javascript that validates a form when I click SEND, to make sure there are no blanks, code is as follows:

function formCheckDancer(formobj){
            // Enter name of mandatory fields
            var fieldRequired = Array("dancerStageName", "dancerFullName", "dancerPhone", "dancerEmail", "dancerCountry", "dancerAvailableDate");

            // Enter field description to appear in the dialog box
            var fieldDescription = Array("Stage Name", "Full Name", "Phone Number", "Email Address", "Nationality", "Availability");

            // dialog message
            var alertMsg = "Please complete the following fields:
";
            var l_Msg = alertMsg.length;

            for (var i = 0; i < fieldRequired.length; i++){
                var obj = formobj.elements[fieldRequired[i]];
                if (obj){
                    switch(obj.type){
                    case "select-one":
                        if (obj.selectedIndex == -1 || obj.options[obj.selectedIndex].text == "" || obj.options[obj.selectedIndex].text == "..."){
                            alertMsg += " - " + fieldDescription[i] + "
";
                        }
                        break;
                    case "select-multiple":
                        if (obj.selectedIndex == -1){
                            alertMsg += " - " + fieldDescription[i] + "
";
                        }
                        break;
                    case "text":
                    case "textarea":
                        if (obj.value == "" || obj.value == null){
                            alertMsg += " - " + fieldDescription[i] + "
";
                        }
                        break;
                    case "checkbox":
                        if (obj.checked == false){
                            alertMsg += " - " + fieldDescription[i] + "
";
                        }
                        break;
                    default:
                    }
                    if (obj.type == undefined){
                        var blnchecked = false;
                        for (var j = 0; j < obj.length; j++){
                            if (obj[j].checked){
                                blnchecked = true;
                            }
                        }
                        if (!blnchecked){
                            alertMsg += " - " + fieldDescription[i] + "
";
                        }
                    }
                }
            }

            if (alertMsg.length == l_Msg){
                return sendDetailsDancer(); //Send email if all field are populated.
                return true;
            }else{
                alert(alertMsg);
                return false;
            }
        }

        function sendDetailsDancer(){
            var stagename = $("input[name=dancerStageName]").val();
            var fullname = $("input[name=dancerFullName]").val();
            var phone = $("input[name=dancerPhone]").val();
            var email = $("input[name=dancerEmail]").val();
            var nationality = $("#dancerCountry").val();
            var availability = $("input[name=dancerAvailableDate]").val();

            $("#contact_form_result_dancer").html('<center><img src="loading.gif" width="32" height="32" /></center>');
            $("#contact_form_result_dancer").show();
            $.post("http://localhost/lapello/wp-content/themes/lapello/sendMailDancer.php", {stagename: stagename, fullname: fullname, phone: phone, email: email, nationality: nationality, availability: availability}, function (data){
                $("#contact_form_result_dancer").html(data);
            });
            setTimeout("contactReturnDancer()", 4000);
            return false;
        }

在这种情况下，国籍是我想要的值.如您所见，我已经尝试过:

In this case Nationality is the value I want. As you can see I've tried:

var nationality = $("#dancerCountry").val();

这似乎不起作用.

如果我把下面的警告语句: alert(obj.options[obj.selectedIndex].text);在 caseselect-one"之后输出正确的值，所以我知道它被正确传递.

If I put the following alert statement: alert(obj.options[obj.selectedIndex].text); after case "select-one" the correct value is output so I know its being passed correctly.

我只是不确定如何在 sendDetailsDancer 函数中捕获它.

I'm just not sure how to capture it in the sendDetailsDancer function.

感谢任何帮助.

问候，斯蒂芬

推荐答案

var nationality = $("#dancerCountry").val(); 应该可以工作.你确定元素选择器工作正常吗?也许你应该试试:

var nationality = $("#dancerCountry").val(); should work. Are you sure that the element selector is working properly? Perhaps you should try:

var nationality = $('select[name="dancerCountry"]').val();

这篇关于JQuery - 获取选择值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！