本文介绍了计算R中的年龄的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在R中有两个数据框。一个框有一个人的出生年份：
I have two data frames in R. One frame has a persons year of birth:
YEAR
/1931
/1924
，然后另一列显示了最近的时间。
and then another column shows a more recent time.
RECENT
09/08/2005
11/08/2005
我想做的是减去年数，以便可以按年数计算他们的年龄，但是我不确定该如何处理。请问有帮助吗？
What I want to do is subtract the years so that I can calculate their age in number of years, however I am not sure how to approach this. Any help please?
推荐答案
以下函数采用Date对象的向量并计算年龄，正确地计算了leap年。似乎是比任何其他答案都更简单的解决方案。
The following function takes a vectors of Date objects and calculates the ages, correctly accounting for leap years. Seems to be a simpler solution than any of the other answers.
age = function(from, to) {
from_lt = as.POSIXlt(from)
to_lt = as.POSIXlt(to)
age = to_lt$year - from_lt$year
ifelse(to_lt$mon < from_lt$mon |
(to_lt$mon == from_lt$mon & to_lt$mday < from_lt$mday),
age - 1, age)
}
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