问题描述
我想构建一个 Map< Item,List< String>>
,即使用 Item
引用作为键,使用一些任意 List< String>
作为值。我尝试了以下内容,但它会在IntelliJ中显示类型推断错误(但是,它仍然会编译);
I want to construct a Map<Item, List<String>>
, i.e. using the Item
reference as key, with some arbitrary List<String>
as value. I've attempted the following, but it will show type inference error in IntelliJ (however, it will still compile);
List<Item> items = getItems(...);
Map<Item, List<String>> itemMap = items.stream().collect(Collectors.toMap(i->i, new ArrayList<>()));
然后,我通过项$ c中的帮助方法创建了一个变通方法$ c>,
get()
,它只返回自己的实例;
I then created a workaround through a helper method in Item
, get()
, which just returns its own instance;
public Item get(){ return this; }
然后尝试使用相同的方法,使用 get()
访问参考的方法:
Then tried the same approach, using the get()
method to access the reference:
List<Item> items = getItems(...);
Map<Item, List<String>> itemMap = items.stream().collect(Collectors.toMap(Item::get, new ArrayList<>()));
现在它至少会编译,但感觉不对。
Now it will at least compile, but it feels wrong.
如何以正确的方式解决这个问题?
How would one actually go around solving this in a proper manner?
编辑:问题现在完全不同从最初发布的内容,反映在收到的评论中。
Question is now radically different from what was originally posted, reflected by the comments received.
推荐答案
实现它的正确方法是包含类型参数,如所以;
The proper way of achieving it was to include a type argument like so;
List<Item> items = getItems(...);
Map<Item, List<String>> itemMap = items.stream().collect(Collectors.toMap(Function.<Item>identity(), v -> new ArrayList<>()));
另外;
List<Item> items = getItems(...);
Map<Item, List<String>> itemMap = items.stream().collect(Collectors.toMap(v -> v, v -> new ArrayList<String>()));
这篇关于使用Streams API和Collectors.toMap()使用对象引用作为键构造Map的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!