问题描述
我试图重组子阵的没有的有 MPI_Gatherv
暗灰色行。图片的千言万语:
I'm trying to recombine sub-arrays without the dark-grey rows with MPI_Gatherv
. Picture's worth a thousand words:
你会如何发送 * sendbuf
(中的),以根进程(无其他结构的浪费改写,这次没有暗灰色行)?在 *位移
(第4个参数)只对相关的 * recvbuf
根的过程。
How would you send only parts of *sendbuf
(the first parameter in MPI_Gatherv manual) to the root process (without a wasteful rewriting in another structure, this time without the dark-grey rows)? The *displacements
(the 4th parameter) is only relevant to the *recvbuf
of the root process.
感谢您。
我想也派边界(浅灰色)细胞......不只是内部(白色)细胞。由于 osgx 正确地指出:在这种情况下, MPI_Gatherv
足以...一些有条件的数组索引会做
I wanted to also send the "boundary" (light-grey) cells ... not just the "interior" (white) cells. As osgx correctly pointed out: in this case the MPI_Gatherv
suffices ... some conditional array indexing will do it.
推荐答案
怎么样构建一个数据类型,这将允许您发送只有白色(室内)细胞?
What about constructing a datatype, which will allow you to send only white (Interior) cells?
合并(来源)数据类型可以是。
The combined (derived) datatype can be a MPI_Type_indexed
.
唯一的问题将是非常第一线,并在过程中P0和PN最后一行,因为P1和PN应该发送更多的数据,那么P2 .... PN-1
The only problem will be with very first line and very last line in processes P0 and PN, because P1 and PN should send more data then P2....PN-1
有关内饰+边界就可以构造一个行的数据类型,以
For Interior+Boundary you can construct datatype of single "line" with
MPI_Datatype LineType;
MPI_Type_vector (1, row_number, 0 , MPI_DOUBLE, &LineType)
MPI_Type_commit ( &LineType);
然后(对数组的大小[I] [J]分裂为 stripecount
条纹)
for (i=0; i< processes_number; ++i) {
displs[i] = i*(I/stripecount)+1; // point to second line in each stripe
rcounts[i] = (I/stripecount) -2 ;
}
rcounts[0] ++; // first and last processes must send one line more
rcounts[processes_number-1] ++;
displs[0] -= 1; // first process should send first line of stripe
// lastprocess displacement is ok, because it should send last line of stripe
source_ptr = ARRAY[displs[rank]];
lines_to_send = rcounts[rank];
MPI_Gatherv( source_ptr, lines_to_send, LineType, recv_buf, rcounts, displs, LineType, root, comm);
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