问题描述
亲爱的朋友,
在这里我想删除一个子字符串:
例如:天使保育学校; 001
我要删除; 001
但是我写了这样的代码:
Dear Friends,
Here i want to Remove a sub string:
Example:Angel Nursery School; 001
i want to Remove ;001
But i have written a code like this:
String text = ddlschoolname.Text;
String numbers = text;
if (text.Length >= 10)
{
numbers = text.Substring(text.Length - 6);
}
但是,如果有任何问题,请不要删除; 001,建议我.
问候,
Anilkumar.D
But the ;001 is not Removing if any thing wrong please suggest me.
Regards,
Anilkumar.D
推荐答案
text.substring(0,text.length-4);
如果每个字符串都包含;那么您可以按如下所示进行拆分
if every string contains ; then you can split as below
string[] str=text.split(';')
//In str[0] you will get school name.
希望这对您有帮助
Hope this helps you
string[] str=text.split(';')
str[0]=Angel Nursery School;
class Program
{
static void Main()
{
string input = "Angel Nursery School; 001";
string sub = input.Substring(6);
Console.WriteLine("Substring: {0}", sub);
}
}
它将返回:托儿所; 001
重载2: Substring(int Starteindex, int Endindex)
-它将返回startindex和Endindex之间的所有字符
例如
It will return : Nursery School; 001
Overload 2: Substring(int Starteindex, int Endindex)
- It will return all the characters between startindex and Endindex
e.g.
class Program
{
static void Main()
{
string input = "Angel Nursery School; 001";
string sub = input.Substring(6, 13);
Console.WriteLine("Substring: {0}", sub);
}
}
它将返回:托儿所
现在回到您的情况.如果要删除001,则将代码修改为:
It will return : Nursery
Now coming back to your case. If you want to remove 001, then modify your code as :
String text = ddlschoolname.Text;
String numbers = text;
if (text.Length >= 10)
{
numbers = text.Substring(0, text.Length - 3);
}
希望这会有所帮助.
一切顺利.
Hope this helps.
All the best.
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