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问题描述

使用 F2Py 来编译 Fortran 例程适合在 Python中使用

code>,下面这段代码在使用 F2Py 时成功编译配置gfortran作为编译器,但是在调用时, Python $ <$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $'函数select(x)result(y)
implicit none
整数,意图(in):: x(:)
整数:: i,j,temp(size(x))
integer,allocatable :: y(:)
j = 0
do i = 1,size(x)
if(x(i)/ = 0)then
j = j + 1
temp(j)= x(i)
endif
enddo
allocate(y(j))
y = temp(:j)
end function select

可以找到类似的StackOverflow文章。

> http://www.shocksolution.com/2009/09/f2py-binding-fortran-python/ ,特别是在示例中,以及
<$的含义p $ p> !f2py depends(len_a)a,bar

然而,作者没有触及生成不同大小数组的问题。


Using F2Py to compile Fortran routines being suitable to be used within Python, the following piece of code is successfully compiled configured gfortran as the compiler while using F2Py, however, at the time of invoking in Python it raises a runtime error!
Any comments and solutions?

function select(x) result(y)
   implicit none
   integer,intent(in):: x(:)
   integer:: i,j,temp(size(x))
   integer,allocatable:: y(:)
   j = 0
   do i=1,size(x)
      if (x(i)/=0) then
         j = j+1
         temp(j) = x(i)
      endif
   enddo
   allocate(y(j))
   y = temp(:j)
end function select

A similar StackOverflow post can be found here.

解决方案

Take a look at this article http://www.shocksolution.com/2009/09/f2py-binding-fortran-python/ , especially at the example and the meaning of

!f2py depend(len_a) a, bar

However, the author does not touch of the problem of generating a an array of different size.

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07-30 01:56