问题描述
有没有办法获取文本字符串的控制字符,例如\\\
for newline
在plotmath表达式内进行评估,反之亦然。在以下示例中,我想结合: - 某些字符文本
- 文本控制字符(换行)
- 替换变量名称
- 包含plotmath表达式
阅读后,我可以使用替代方式获得大部分方式,但 newline
不评估字符。我现在正在循环,并将自己与 plotmath
, parse
, bquote
和替换
。在进行绘图,它说
这是不是真的是不可能的?
lab =some数据
form =指数
x = 1:10
y = x ^ 2
plot(x,y,type =b )
title(main = substitute(paste(Plot of,phi,of:,lab,\\\
Functional form:,form),list(lab = lab,form = form) adj = 0)
正如你所想的 plotmath
不支持换行,但您可以使用 mtext
与 bquote
,以写每行。例如,我创建一个行列表:
行< - list(bquote(paste(Plot of,phi, (。),(实验室)))
bquote(粘贴(功能形式:,。(形式)))
mtext(do.call ,side = 3,line = 1:0)
Is there any way to get control characters for text strings, e.g. "\n"
for newline
evaluated inside a plotmath expression, or vice versa. In the following example, I would like to combine:
- some character text
- text control character (newline)
- substitute a variable name
- include a plotmath expression
After reading this question I can get most of the way there with substitute, but the newline
character is not evaluated. I am now going round in circles and confusing myself with plotmath
, parse
, bquote
and substitute
. In the help page for plotmath it says
Does this mean it really is impossible?
lab = "some data"
form = "Exponential"
x = 1:10
y = x^2
plot( x , y , type = "b" )
title( main = substitute( paste( "Plot of " , phi , " of: " , lab , "\nFunctional form: " , form ) , list(lab = lab , form = form ) ) , adj = 0 )
As you have figured plotmath
does not support newlines within, but you can use mtext
with bquote
, to write each line. For example I create a list of lines :
Lines <- list(bquote(paste( "Plot of " , phi , " of: " , .(lab))),
bquote(paste("Functional form: " , .(form)))
mtext(do.call(expression, Lines),side=3,line=1:0)
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