问题描述
使用Dev C ++ 4
用户可以输入城市和临时名称，
但是当它输出城市名称时我会得到垃圾但是
temps很好。
struct Cities {
char city [];
int temp;
} ;
void input_names（Cities info []，int numb_cities）{
for（int t = 0; t< numb_cities; t ++）{
cout<<" \ n\ n" ;;
cout<<"请输入城市名称＃"<< t + 1<< ;"：" ;; cin>> info [t] .city;
cout<<" \ nplease输入城市的临时温度"
< ;< info [t] .city<<"：" ;;
cin>> info [t] .temp;
}
cout<<" \ n\\\
" ;;
for（int t = 0; t< numb_cities; t ++）{
cout<< info [t] .city<<" "<< info [t] .temp<<" \ n" ;;
}
} //关闭input_names;
void main（）{
int n，
numb_cities = 10; //城市数量
void input_names（Cities []，int）;
城市信息[numb_cities];
input_names（info，numb_cities）;
}
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using Dev C++4
user can enter names of cities and temps,
but when it output city names i get garbage but
temps are fine.
struct Cities {
char city[];
int temp;
};
void input_names(Cities info[], int numb_cities) {
for(int t=0;t<numb_cities;t++) {
cout<<"\n\n";
cout<<"please enter name of city#"<<t+1<<": ";cin>>info[t].city;
cout<<"\nplease enter temp of city "
<<info[t].city<<": ";
cin>>info[t].temp;
}
cout<<"\n\n";
for(int t=0;t<numb_cities;t++) {
cout<<info[t].city<<" "<<info[t].temp<<"\n";
}
}//close input_names;
void main() {
int n,
numb_cities=10; //number of cities
void input_names(Cities[], int);
Cities info[numb_cities];
input_names(info, numb_cities);
}
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推荐答案
问题是cin>> char []不分配存储空间，你需要
才能做到这一点。 std :: string完成分配存储的所有魔力和
清理它。
The problem is that cin >> char [] does not allocate storage, you need
to do that. std::string does all the magic of allocating storage and
cleaning it up.
这也不合法。 C ++中的数组声明需要大小不变
表达式（我打赌你使用的是一个简单的G ++）。
我建议你得到一个体面的C ++文本。我认为Koenig& Moo''s Accellerated C ++
对你非常有帮助。
This is also not legal. Array declarations in C++ need sizes that are constant
expressions (I bet you''re using an anceint G++).
I''d recommend you get a decent C++ text. I think Koenig & Moo''s Accellerated C++
will be very helpful to you.
必须返回int。
main must return int.
为什么会这样？
返回到哪里？
程序编译得很好。
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why is that?
return to where?
the program compiles fine as it is.
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