问题描述
我想启动资源管理器并选择一个特定的文件.所以我跑
I want to start explorer and select a specific file. So I run
QProcess::startDetached(command);
,其中 command 设置为
explorer.exe /select,C:\Users\....\file.txt
这可以正常工作,但是如果文件路径包含空格,将失败.但是如果我把路径放在引号中
This works fine, but will fail if the path to the file contains spaces. But if I put the path in quotes
explorer.exe /select,"C:\Users\....\file.txt"
资源管理器将打开documents文件夹,而不是指定的路径.从命令行运行相同的字符串可以正常工作.
the explorer will open the documents folder and not the specified path.Running the same string from the command line works fine.
该字符串用
command = "explorer.exe" + "/select," + "\"" + QDir::toNativeSeparators(path) + "\"";
推荐答案
如何实现这一目标确实不是那么直观,但也不是不可能.
How to achieve this is indeed not so intuitive, but also not impossible.
将命令 explorer.exe
的所有参数分解为单独的字符串,即/select
,,
, the_path
.
Decompose all arguments of the command, explorer.exe
, as separate strings, i.e. /select
, ,
, the_path
.
QProcess::startDetached("explorer.exe", QStringList{"/select", ",", "C:\\Users\\Your Username\\Desktop\\Folder With Spaces\\file.txt"});
这篇关于当指定文件的路径包含空格时,如何使用QProcess启动explorer.exe?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!