本文介绍了使用半径或距离定义邻居海龟的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想使用半径或距离来定义邻居.到目前为止,我的解决方案是:

I would like to define neighbors using in-radius or distance. My solution so far is:

turtles-own [
  my-neighbors
  num-neighbors]

to setup

ca
crt 100 [
  move-to one-of patches with [ not any? turtles-here ]
  set my-neighbors (other turtles) in-radius 3
  set num-neighbors count my-neighbors
]

end

问题是大多数乌龟都有0到4个邻居,但其中一些却有相对较多的邻居(例如34和65).这些乌龟位于世界中心附近.

The problem with this is that most of the turtles have between 0 to 4 neighbors, but a few of them have a relatively huge number of neighbors (e.g., 34 and 65). Those turtles are located close to the center of the world.

关于我在做什么错的任何想法吗?

Any ideas about what I am doing wrong?

推荐答案

这与程序中出现副作用的时间有关.

It has to do with the timing of side effects in your program.

假设第一个要移动的乌龟在中心附近移动.其他乌龟尚未移动,因此它们都仍在patch 0 0上,并且set my-neighbors (other turtles) in-radius 3将捕获它们.即使它们移到其他地方,它们仍将包含在第一个乌龟的my-neighbors代理集中.

Suppose that the very first turtle to move moves near the center. None of the other turtles have moved yet, so they're all still on patch 0 0 and set my-neighbors (other turtles) in-radius 3 will capture them all. And even after they move elsewhere, they will still be included in the first turtle's my-neighbors agentset.

您可以通过首先移动所有海龟然后计算它们的邻居来避免问题,

You can avoid the problem by first moving all the turtles and then calculate their neighbors:

to setup
  clear-all
  crt 100 [
    move-to one-of patches with [ not any? turtles-here ]
  ]
  ask turtles [
    set my-neighbors (other turtles) in-radius 3
    set num-neighbors count my-neighbors
  ]
end

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09-11 20:15