问题描述
如果我有一个填满屏幕的 ImageView.
ImageView 背景设置为绿色.
我在 ImageView 中放置了一个位图，保持位图比例.
If i have an ImageView that fills the screen.
The ImageView background is set to green color.
I place a bitmap in the ImageView, keeping bitmap proportions.
此布局中的纵向照片将在左侧和右侧显示绿色
(手机方向=纵向).
A portrait photo in this layout will show green on both left and right side
(Phone orientation= portrait).
现在，当绿色结束并且位图开始时，我如何获得边缘的左侧 x/y 位置.
Now, How do i get the left side x/y position of the edge when the green ends and bitmap begins.
这个努力项目的背景是我想在图像上写文本并将图像保存回带有文本的新图像.问题是..
The background for this endeavor project is that i want to write text on the image and save the image back to a new image with the text. The problem is..
由于我将图像缩放为 inSampleSize = 4;并且 ImageView 进一步缩小它，保存这张新图片将给出一个大约 250x350 的小图像.
Since I scale the image inSampleSize = 4; and the ImageView shrinking it even more, saving this new picture will give a small small approx 250x350 image.
我想要的是使用 x/y 位置并将书面文本传输到原始 inSampleSize = 4 图像或 sdcard 1500x3000 图像
What i want is to use the x/y positions and transfer the written text to the original inSampleSize = 4 image or to the sdcard 1500x3000 image
我知道并阅读过其他有关我必须自己进行数学计算"的问题我只需要这个小答案.
I know and read other questions about this that i have to "Do the math calculations" myselfI just need this small answer.
我忘了我可以截图澄清一下.
I forgot i can take a screenshot to clarify.
这就是它的样子:(按下笔"按钮我得到一支新笔，每支笔都有自己独特的文本和屏幕上的位置
this is what it look like: (I get a new pen on pressing the button "pen" each pen hold its own unique text and position on the screen
这是图像视图
import java.util.HashMap;
import java.util.UUID;
import android.app.Activity;
import android.content.Context;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Point;
import android.graphics.Rect;
import android.graphics.Typeface;
import android.graphics.drawable.BitmapDrawable;
import android.graphics.drawable.Drawable;
import android.os.Environment;
import android.util.AttributeSet;
import android.view.Display;
import android.view.MotionEvent;
import android.widget.EditText;
import android.widget.ImageView;
public class DrawView2 extends ImageView {
private HashMap<String, ColorBall2> HashBall ;
private String balID = ""; // variable to know what ball is being dragged
public final String PTPPSERVICE_DERECTORY = "/PTPPservice/";
private Bitmap bitmap;
private EditText ed;
private Paint paint = new Paint();
private Paint paint2 = new Paint();
private Paint pTouch = new Paint();
private EditText addtext;
private Context ctx;
private String imagePath;
private boolean removeBall = false;
int viewWidth = 0;
int viewHeight = 0;
double bitmapHight =0;
double bitmapWidth =0;
double ratio =0;
double startX = 0;
double endX= 0;
double startY= 0;
double endY = 0;
public DrawView2(Context context, AttributeSet atts,String image1) {
super(context, atts);
this.ctx = context;
this.imagePath = image1;
setFocusable(true);
paint.setStyle(Paint.Style.FILL_AND_STROKE);
paint.setColor(Color.BLACK);
paint.setTypeface(Typeface.DEFAULT_BOLD);
paint2.setStyle(Paint.Style.FILL_AND_STROKE);
paint2.setColor(Color.RED);
addtext = (EditText) ((Activity) ctx).findViewById(R.id.edittextaddtext);
String filePath = Environment.getExternalStorageDirectory().toString() + imagePath;
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 4;
bitmap = BitmapFactory.decodeFile(filePath,options);
// SAVE RATIO
int x = bitmap.getWidth();
int y = bitmap.getHeight();
if(y>x)
ratio = ((double)y)/x;
if(x>y)
ratio = ((double)x)/y;
if(y==x)
ratio = 1;
Drawable bit = new BitmapDrawable(bitmap);
setImageDrawable(bit);
}
public double getRatio() {
return ratio;
}
public HashMap<String, ColorBall2> getHashBall() {
return HashBall;
}
// RETURN THE ON SCREEN RESIZED BITMAP
public double getOnScreenBitmapHight(){
return bitmapHight;
}
public double getOnScreenBitmapWidth(){
return bitmapWidth;
}
// BITMAP SIZE
public int getBitmapHight(){
return bitmap.getHeight();
}
public int getBitmapWidth(){
return bitmap.getWidth();
}
// GET IMAGEVIEW HIGHT WIDTH
public int getViewWidth() {
return viewWidth;
}
public int getViewHeight() {
return viewHeight;
}
// START END X Y
public double getStartX() {
return startX;
}
public double getEndX() {
return endX;
}
public double getStartY() {
return startY;
}
public double getEndY() {
return endY;
}
// SET BALL TEXT
public void addTextToBall(String text) {
if(balID != "")
HashBall.get(balID).setText(text);
}
// PATH
public String getImagePath() {
return imagePath;
}
// THE ORIGINAL INSAMPELSIZE=4 BITMAP
public Bitmap getBitmap() {
return bitmap;
}
// STOP DRAWAING THE BALL
public void removeBall(boolean value) {
removeBall = value;
}
// THE RECT THAT RETURN WRONG VALUE
public Rect getRect(){
Rect r = getDrawable().copyBounds();
int drawLeft = r.left;
int drawTop = r.top;
int drawRight = r.right;
int drawBottom = r.bottom;
return r;
}
@Override
protected void onSizeChanged(int xNew, int yNew, int xOld, int yOld){
super.onSizeChanged(xNew, yNew, xOld, yOld);
viewWidth = xNew;
viewHeight = yNew;
}
public void addBall(){
// HERE I TRY TO CALCULATE THE BOUNDS LEFT,RIGHT,TOP AND BOTTOM EDGE OF THE BITMAP
//NOT GOING THAT GOOD
if(HashBall == null)
HashBall = new HashMap<String,ColorBall2>();
//X
double drawAbleWidth = viewWidth/ratio;
startX = (viewWidth-drawAbleWidth)/2;
double drawAbleHight = viewHeight/ratio;
startY = drawAbleHight/2;
int ballY = (viewHeight/2);
int ballX = (viewWidth/2);
Point point1 = new Point();
point1.x = (int) ballX;
point1.y = (int) ballY;
String uuId = UUID.randomUUID().toString();
HashBall.put(uuId,(new ColorBall2(ctx,R.drawable.pen1, point1,uuId)));
}
@Override
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
//canvas.drawCircle(10,10,10,null);
if(!removeBall && HashBall != null){
for (String key : HashBall.keySet()) {
//System.out.println("Key: " + key + ", Value: " + map.get(key));
if(addtext!=null)
//canvas.drawCircle(HashBall.get(key).getX(), HashBall.get(key).getY(), 10, paint2);
canvas.drawBitmap(HashBall.get(key).getBitmap(), HashBall.get(key).getX()-10, HashBall.get(key).getY()-80, null);
canvas.drawText (HashBall.get(key).getText() + " X="+HashBall.get(key).getX() + " Y="+HashBall.get(key).getY()
, HashBall.get(key).getX(), HashBall.get(key).getY(), paint);
}
}
}
// events when touching the screen
@Override
public boolean onTouchEvent(MotionEvent event) {
int eventaction = event.getAction();
int X = (int)event.getX();
int Y = (int)event.getY();
switch (eventaction )
{
case MotionEvent.ACTION_DOWN: // touch down so check if the finger is on a ball
balID = "";
for (String key : HashBall.keySet()) {
// check if inside the bounds of the ball (circle)
// get the center for the ball
int centerX = HashBall.get(key).getX() + 15;
int centerY = HashBall.get(key).getY() + 15;
// calculate the radius from the touch to the center of the ball
double radCircle = Math.sqrt( (((centerX-X)*(centerX-X)) + (centerY-Y)*(centerY-Y)));
// if the radius is smaller then 23 (radius of a ball is 22), then it must be on the ball
if (radCircle < 33){
balID = HashBall.get(key).getID();
addtext.setText(HashBall.get(key).getText());
break;
}
}
break;
case MotionEvent.ACTION_MOVE: // touch drag with the ball
// move the balls the same as the finger
if (balID != "") {
HashBall.get(balID).setX(X-25);
HashBall.get(balID).setY(Y-25);
}
break;
case MotionEvent.ACTION_UP:
// touch drop - just do things here after dropping
break;
}
// redraw the canvas
invalidate();
return true;
}
}
推荐答案
如果您知道比率，您可以推导出将放置在图像一侧的边距的宽度.
If you know the ratios you can just derive the width of the margin that will be placed to the side of the image.
// These holds the ratios for the ImageView and the bitmap
double bitmapRatio = ((double)bitmap.getWidth())/bitmap.getHeight()
double imageViewRatio = ((double)imageView.getWidth())/imageView.getHeight()
现在，如果 bitmapRatio 大于 imageViewRatio，你知道这意味着如果它们具有相同的高度，则 bitmap 比 imageview 宽.换句话说，您将在顶部有空白 &底部.
Now, if the bitmapRatio is larger than the imageViewRatio, you know that this means that the bitmap is wider than the imageview if they have an equal height. In other words, you'll have blanks on the top & bottom.
相反，如果 bitmapRatio 小于 imageViewRatio，那么您的左右两侧将出现空白.从这里你可以很简单地得到一个坐标，因为它会是 0！
Conversely, if bitmapRatio is smaller than imageViewRatio then you'll have blanks to the left and right. From this you can get one of the co-ordinates pretty trivially as it'll be 0!
if(bitmapRatio > imageViewRatio)
{
drawLeft = 0;
}
else
{
drawTop = 0;
}
要获得另一个坐标，请考虑第二种情况，即您还有空间 &对.这里位图和 imageView 的高度相等，因此宽度之间的比率等于比率之间的比率.您可以使用它来计算位图的宽度，因为您知道 imageView 的宽度.同样，如果宽度相等，您可以计算出高度，除了您必须使用比率之间的比率的倒数，因为宽度与比率成反比:
To get the other co-ordinate, think about the second case where you have space left & right. Here the heights of the the bitmap and imageView are equal and thus the ratio between the widths is equal to ratio between the ratios. You can use this to figure out width of the bitmap as you know the width of the imageView. Similarly you can figure out the heights if the width are equal, except that you have to use the inverse of the ratio between the ratios as the width is inversely proportional the the ratio:
if(bitmapRatio > imageViewRatio)
{
drawLeft = 0;
drawHeight = (imageViewRatio/bitmapRatio) * imageView.getHeight();
}
else
{
drawTop = 0;
drawWidth = (bitmapRatio/imageViewRatio) * imageView.getWidth();
}
一旦你有了位图的宽度或高度，将空间移到一边很简单，它只是位图和 imageView 宽度或高度之差的一半:
Once you have the width or height of the bitmap, getting the space to the side is simple, it is just half the difference between the bitmap and imageView width or height:
if(bitmapRatio > imageViewRatio)
{
drawLeft = 0;
drawHeight = (imageViewRatio/bitmapRatio) * imageView.getHeight();
drawTop = (imageView.getHeight() - drawHeight)/2;
}
else
{
drawTop = 0;
drawWidth = (bitmapRatio/imageViewRatio) * imageView.getWidth();
drawLeft = (imageView.getWidth() - drawWidth)/2;
}
这篇关于android - 如何在imageview中获取图像边缘x/y位置的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！