问题描述
这个错误是什么意思?我如何解决它?
what does this error mean? and how do i solve it?
foreach不适用于表达式类型。
foreach not applicable to expression type.
我正在尝试写一个方法find()。在链表中查找字符串
im am trying to write a method find(). that find a string in a linkedlist
public class Stack<Item>
{
private Node first;
private class Node
{
Item item;
Node next;
}
public boolean isEmpty()
{
return ( first == null );
}
public void push( Item item )
{
Node oldfirst = first;
first = new Node();
first.item = item;
first.next = oldfirst;
}
public Item pop()
{
Item item = first.item;
first = first.next;
return item;
}
}
public find
{
public static void main( String[] args )
{
Stack<String> s = new Stack<String>();
String key = "be";
while( !StdIn.isEmpty() )
{
String item = StdIn.readString();
if( !item.equals("-") )
s.push( item );
else
StdOut.print( s.pop() + " " );
}
s.find1( s, key );
}
public boolean find1( Stack<String> s, String key )
{
for( String item : s )
{
if( item.equals( key ) )
return true;
}
return false;
}
}
这是我的全部代码
推荐答案
您使用的是迭代器而不是数组吗?
Are you using an iterator instead of an array?
Iterator<Penguin> it = colony.getPenguins();
for (Penguin p : it) {
错误:
BadColony.java:36: foreach not applicable to expression type
for (Penguin p : it) {
我刚看到你有自己的Stack类。您确实意识到SDK中已有一个,对吧?
您需要实现 Iterable
界面才能使用此格式的 for
loop:
I just saw that you have your own Stack class. You do realize that there is one already in the SDK, right? http://download.oracle.com/javase/6/docs/api/java/util/Stack.htmlYou need to implement Iterable
interface in order to use this form of the for
loop: http://download.oracle.com/javase/6/docs/api/java/lang/Iterable.html
这篇关于foreach不适用于表达类型的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!