本文介绍了如何使线程不会冻结整个 JFrame.JAVA的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

嘿,我只需要回答一个问题...如何使以下代码不冻结我的整个 JFrame?

Hey i just need a question answered...How would i make the following code not freeze my whole JFrame?

                try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch(InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

推荐答案

使用不同的线程来执行这个任务.如果您在主 UI 线程中执行此操作,那么它将冻结.例如,您可以执行以下操作

use a different thread to perform this task. If you do this in the main UI thread then it will freeze.. For example you can do following

  new Thread() {

        @Override
        public void run() {
            try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch (InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

        }
    }.start();

更新

在 Robin 和 Marko 的明智建议之后,我正在用更好的解决方案更新答案.

AFter wise suggestions of Robin and Marko I am updating the answer with a better solution.

    ActionListener taskPerformer = new ActionListener() {
        public void actionPerformed(ActionEvent evt) {
                System.out.println("Hello!");

        }
    };
    javax.swing.Timer t = new javax.swing.Timer(Integer.parseInt(delayField.getText()) * 1000, taskPerformer);
    t.setRepeats(false);
    t.start();

这篇关于如何使线程不会冻结整个 JFrame.JAVA的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-29 20:19