如何使线程不会冻结整个 JFrame.JAVA

问题描述

嘿，我只需要回答一个问题...如何使以下代码不冻结我的整个 JFrame?

Hey i just need a question answered...How would i make the following code not freeze my whole JFrame?

                try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch(InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

推荐答案

使用不同的线程来执行这个任务.如果您在主 UI 线程中执行此操作，那么它将冻结.例如，您可以执行以下操作

use a different thread to perform this task. If you do this in the main UI thread then it will freeze.. For example you can do following

  new Thread() {

        @Override
        public void run() {
            try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch (InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

        }
    }.start();

更新

在 Robin 和 Marko 的明智建议之后，我正在用更好的解决方案更新答案.

AFter wise suggestions of Robin and Marko I am updating the answer with a better solution.

    ActionListener taskPerformer = new ActionListener() {
        public void actionPerformed(ActionEvent evt) {
                System.out.println("Hello!");

        }
    };
    javax.swing.Timer t = new javax.swing.Timer(Integer.parseInt(delayField.getText()) * 1000, taskPerformer);
    t.setRepeats(false);
    t.start();

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