本文介绍了如何将Java 8流收集到Guava ImmutableCollection中?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想执行以下操作:
List<Integer> list = IntStream.range(0, 7).collect(Collectors.toList());
但是结果列表是Guava的 ImmutableList 。
but in a way that the resulting list is an implementation of Guava's ImmutableList
.
我知道我能做到
List<Integer> list = IntStream.range(0, 7).collect(Collectors.toList());
List<Integer> immutableList = ImmutableList.copyOf(list);
但我想直接收款。我试过了
but I would like to collect to it directly. I've tried
List<Integer> list = IntStream.range(0, 7)
.collect(Collectors.toCollection(ImmutableList::of));
但它引发了一个例外:
推荐答案
Alexis接受的答案中的 toImmutableList()
方法现在包含在,可以用作:
The toImmutableList()
method in the accepted answer of Alexis is now included in Guava 21 and can be used as:
ImmutableList<Integer> list = IntStream.range(0, 7)
.boxed()
.collect(ImmutableList.toImmutableList());
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