问题描述
我正在尝试将指向UInt16数组的指针的指针发送给编组函数,如C#中这样:
I'm attempting to send a pointer to a pointer of a UInt16 array to a marshalled function like so in C#:
C ++:
int foo(Unsigned_16_Type** Buffer_Pointer);
C#:
[DllImport("example.dll")]
public static extern int foo(IntPtr Buffer_Pointer);
UInt16[] bufferArray = new UInt16[32];
IntPtr p_Buffer = (IntPtr)Marshal.AllocCoTaskMem(Marshal.SizeOf(typeof(UInt16)) * bufferArray.Length);
Marshal.Copy(bufferArray, 0, p_Buffer, bufferArray.Length); //Issue is here
GCHandle handle = GCHandle.Alloc(p_Buffer, GCHandleType.Pinned);
IntPtr ppUnmanagedBuffer = (IntPtr)handle.AddrOfPinnedObject();
UInt16 word_count = 0;
this.lstbox_DATA_WORDS.Items.Clear();
if ( foo(ppUnmanagedBuffer );
我的主要问题是Marshal.Copy
,对于第一个参数(即源数组),它不使用UInt16[]
.我想知道是否有人知道如何将Marshal.Copy
与UInt16
数组一起使用.
My main problem is with the Marshal.Copy
, for the first argument which is the source array, it does not take a UInt16[]
. I was wondering if anyone knew how to use Marshal.Copy
with a UInt16
array.
推荐答案
不存在采用无符号短数组的Marshal.Copy
重载.幸运的是,ushort
和short
的大小相同,因此可以使用Marshal.Copy(Int16[], IntPtr, int)
重载.您只需要先将ushort[]
强制为short[]
.
There is no Marshal.Copy
overload that takes an unsigned short array. Fortunately, ushort
and short
are the same size, so you can use the Marshal.Copy(Int16[], IntPtr, int)
overload. You just need to coerce your ushort[]
into a short[]
first.
可能最快的方法是使用 .它复制字节,所以您只需要告诉它每个条目复制2个字节即可:
Probably the fastest way to do this is to use Buffer.BlockCopy
. It copies bytes, so you just have to tell it to copy 2 bytes per entry:
short[] temp = new short[bufferArray.Length];
System.Buffer.BlockCopy(bufferArray, 0, temp, 0, temp.Length * 2);
这会将无符号的16位整数值复制到一个有符号的16位整数数组中,但是基础字节值将保持不变,并且非托管代码将不知道它们之间的区别.
This will copy the unsigned 16-bit integer values into a signed 16-bit integer array, but the underlying byte values will remain the same, and the unmanaged code won't know the difference.
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